XSLT 连接重复元素的不同值

Question

我有一个要求，我将按如下方式获得 XML：

<Input>
    <Record>
        <EMPID>FirstEmployee</EMPID>
    </Record>           
    <Record>
        <EMPID>SecondEmployee</EMPID>
    </Record>
    <Record>
        <EMPID>FirstEmployee</EMPID>
    </Record>           
    <Record>
        <EMPID>SecondEmployee</EMPID>
    </Record>
</Input>

我在应用转换后对上述 xml 的预期输出是：

<Output>
    <Record>
        <EMPID>FirstEmployee|1</EMPID>
    </Record>
    <Record>
         <EMPID>SecondEmployee|1</EMPID>
    </Record>
    <Record>
         <EMPID>FirstEmployee|2</EMPID>
    </Record>
    <Record>
         <EMPID>SecondEmployee|2</EMPID>
    </Record>
</Output>

当以这种方式使用其中一种解决方案时

<?xml version="1.0" encoding="UTF-8" ?>
<?oracle-xsl-mapper
  <!-- SPECIFICATION OF MAP SOURCES AND TARGETS, DO NOT MODIFY. -->
  <mapSources>
    <source type="WSDL">
      <schema location="../BPELProcess1.wsdl"/>
      <rootElement name="Input" namespace="http://xmlns.oracle.com/UMSAdapterVerify/XSLTCheck/BPELProcess1"/>
    </source>
  </mapSources>
  <mapTargets>
    <target type="WSDL">
      <schema location="../BPELProcess1.wsdl"/>
      <rootElement name="Output" namespace="http://xmlns.oracle.com/UMSAdapterVerify/XSLTCheck/BPELProcess1"/>
    </target>
  </mapTargets>
  <!-- GENERATED BY ORACLE XSL MAPPER 11.1.1.7.8(build 150622.2350.0222) AT [FRI DEC 16 15:55:29 IST 2016]. -->
?>
<xsl:stylesheet version="1.0"
    xmlns:bpws="http://schemas.xmlsoap.org/ws/2003/03/business-process/"
    xmlns:xp20="http://www.oracle.com/XSL/Transform/java/oracle.tip.pc.services.functions.Xpath20"
    xmlns:mhdr="http://www.oracle.com/XSL/Transform/java/oracle.tip.mediator.service.common.functions.MediatorExtnFunction"
    xmlns:bpel="http://docs.oasis-open.org/wsbpel/2.0/process/executable"
    xmlns:client="http://xmlns.oracle.com/UMSAdapterVerify/XSLTCheck/BPELProcess1"
    xmlns:oraext="http://www.oracle.com/XSL/Transform/java/oracle.tip.pc.services.functions.ExtFunc"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:dvm="http://www.oracle.com/XSL/Transform/java/oracle.tip.dvm.LookupValue"
    xmlns:hwf="http://xmlns.oracle.com/bpel/workflow/xpath"
    xmlns:plnk="http://docs.oasis-open.org/wsbpel/2.0/plnktype"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:med="http://schemas.oracle.com/mediator/xpath"
    xmlns:ids="http://xmlns.oracle.com/bpel/services/IdentityService/xpath"
    xmlns:bpm="http://xmlns.oracle.com/bpmn20/extensions"
    xmlns:xdk="http://schemas.oracle.com/bpel/extension/xpath/function/xdk"
    xmlns:xref="http://www.oracle.com/XSL/Transform/java/oracle.tip.xref.xpath.XRefXPathFunctions"
    xmlns:xsd="http://www.w3.org/2001/XMLSchema"
    xmlns:wsdl="http://schemas.xmlsoap.org/wsdl/"
    xmlns:ora="http://schemas.oracle.com/xpath/extension"
    xmlns:socket="http://www.oracle.com/XSL/Transform/java/oracle.tip.adapter.socket.ProtocolTranslator"
    xmlns:ldap="http://schemas.oracle.com/xpath/extension/ldap"
    exclude-result-prefixes="xsi xsl client plnk xsd wsdl bpws xp20 mhdr bpel oraext dvm hwf med ids bpm xdk xref ora socket ldap">
  <xsl:template match="/">
    <client:Output>
      <xsl:for-each select="/client:Input/client:Record">
        <client:Record>
          <xsl:variable name="current" select="."/>
          <xsl:variable name="pos">
            <xsl:number level="any" count="client:EMPID[.=$current]"/>
          </xsl:variable>
          <client:EMPID>
            <xsl:value-of select='concat(.,"|",$pos)'/>
          </client:EMPID>
        </client:Record>
      </xsl:for-each>
    </client:Output>
  </xsl:template>
</xsl:stylesheet>

输出是

<Output>
    <client:Record>
        <client:EMPID> Srinivas |0</client:EMPID>
    </client:Record>
    <client:Record>
        <client:EMPID> kalyan |0</client:EMPID>
    </client:Record>
    <client:Record>
        <client:EMPID> Srinivas |0</client:EMPID>
    </client:Record>
    <client:Record>
        <client:EMPID> kalyan |0</client:EMPID>
    </client:Record>
</Output>

谁能帮忙解决这个问题

Answer 1

试试这个：

<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:template match="@*|node()">
   <xsl:copy><xsl:apply-templates select="@*|node()"/></xsl:copy>
</xsl:template>

<xsl:template match="EMPID">
    <xsl:variable name="varPresentValue"><xsl:value-of select="."/></xsl:variable>
    <xsl:copy>
      <xsl:value-of select="concat(., '|', count(preceding::EMPID[.=$varPresentValue])+1)"/>
    </xsl:copy>
</xsl:template>

<xsl:template match="Input">
    <Output><xsl:apply-templates/></Output>
</xsl:template>

</xsl:stylesheet>

Answer 2

这是一个使用 xsl:number...

的选项

XML 输入

<Input>
    <Record>
        <EMPID>FirstEmployee</EMPID>
    </Record>           
    <Record>
        <EMPID>SecondEmployee</EMPID>
    </Record>
    <Record>
        <EMPID>FirstEmployee</EMPID>
    </Record>           
    <Record>
        <EMPID>SecondEmployee</EMPID>
    </Record>
</Input>

XSLT 1.0

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output indent="yes"/>
  <xsl:strip-space elements="*"/>

  <xsl:template match="@*|node()">
    <xsl:copy>
      <xsl:apply-templates select="@*|node()"/>
    </xsl:copy>
  </xsl:template>

  <xsl:template match="/Input">
    <Output>
      <xsl:apply-templates/>
    </Output>
  </xsl:template>

  <xsl:template match="EMPID">
    <xsl:variable name="current" select="."/>
    <xsl:variable name="pos">
      <xsl:number level="any" count="EMPID[.=$current]"/>
    </xsl:variable>
    <xsl:copy>
      <xsl:value-of select="concat(.,'|',$pos)"/>
    </xsl:copy>
  </xsl:template>

</xsl:stylesheet>

XML输出

<Output>
   <Record>
      <EMPID>FirstEmployee|1</EMPID>
   </Record>
   <Record>
      <EMPID>SecondEmployee|1</EMPID>
   </Record>
   <Record>
      <EMPID>FirstEmployee|2</EMPID>
   </Record>
   <Record>
      <EMPID>SecondEmployee|2</EMPID>
   </Record>
</Output>

编辑更新问题...

您的 xsl:for-each 正在 selecting client:Record，因此您需要将 current 变量更新为 select child client:EMPID。您还应该计算 client:Record 个元素而不是 client:EMPID.

例子

<xsl:template match="/">
  <client:Output>
    <xsl:for-each select="client:Input/client:Record">
      <client:Record>
        <xsl:variable name="current" select="client:EMPID"/>
        <xsl:variable name="pos">
          <xsl:number level="any" count="client:Record[client:EMPID=$current]"/>
        </xsl:variable>
        <client:EMPID>
          <xsl:value-of select='concat(.,"|",$pos)'/>
        </client:EMPID>
      </client:Record>
    </xsl:for-each>
  </client:Output>
</xsl:template>

Answer 3

如果你想要的只是 distinct 个值，你可以简单地做：

XSLT 1.0

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>

<!-- identity transform -->
<xsl:template match="@*|node()">
    <xsl:copy>
        <xsl:apply-templates select="@*|node()"/>
    </xsl:copy>
</xsl:template>

<xsl:template match="/Input">
    <Output>
        <xsl:apply-templates/>
    </Output>
</xsl:template>

<xsl:template match="EMPID">
    <xsl:copy>
        <xsl:value-of select="."/>
        <xsl:text>|</xsl:text>
        <xsl:value-of select="generate-id()"/>      
    </xsl:copy>
</xsl:template>

</xsl:stylesheet>

这比重复计算前面的兄弟节点或对相似节点进行编号要有效得多。

XSLT 连接重复元素的不同值

XSLT to concate distinct values for repeated elements

xslt

xslt-2.0

xslt-1.0