否时是否可以通过多次调用创建模拟。和参数类型未知？

Question

我想知道当我们最初不知道该方法的参数数量时，我们能否创建一个 phpunit 模拟当我们知道方法调用的数量时，通常我们会做这样的事情

mockResponse->expects($this->exactly(2))
    -> method('tmpFunc')
    ->withConsecutive(['header1'], ['header2']);

我想做的是让它变得更有活力

function mockMethod($n, $params) // $params is an array of strings
{
    $mockResponse = $this->getMockBuilder('PMA\libraries\Response')
        ->disableOriginalConstructor()
        ->setMethods(array('tempFunc', 'headersSent'))
        ->getMock();

    if($n > 1)
    {
        $mockResponse->expects($this->exactly($n))
            ->method('tempFunc')
            ->withConsecutive( //todo );

        $mockResponse->expects($this->any())
            ->method('headersSent')
            ->with()
            ->will($this->returnValue(false));

    }
}

例如，如果 $n = 2 和 $params = array('HTTP/1.1 303 See Other', 'Location: index.php?lang=en') 那么函数应该这样做

$mockResponse = $this->getMockBuilder('PMA\libraries\Response')
        ->disableOriginalConstructor()
        ->setMethods(array('tempFunc', 'headersSent'))
        ->getMock();

$mockResponse->expects($this->exactly($n))
    ->method('tempFunc')
    ->withConsecutive([$params[1]], [$params[2]]);

$mockResponse->expects($this->any())
        ->method('headersSent')
        ->with()
        ->will($this->returnValue(false));

我应该如何替换待办事项，以便如果 $n = 2 那么每个字符串都将作为参数发送给 tempFunc()。

public function tempFunc($text)
{
    header($text);
}

public function headersSent()
{
    return headers_sent();
}

Answer 1

我终于从认识的人那里得到了答案

$header_method = $mockResponse->expects($this->exactly(count($param)))
            ->method('tmpFunc');
call_user_func_array(array($header_method, 'withConsecutive'), $param);

否时是否可以通过多次调用创建模拟。和参数类型未知？

Is it possible to create mock with multiple calls when the no. and type of arguments are unknown?

php

phpunit

mocking