PHP 替换 src link 并保留 url

Question

我有这样的源代码：

<script type='text/javascript' src='http://html.com/wp-content/plugins/contact-form-7/includes/js/scripts.js?ver=4.6'></script>
<script type='text/javascript'></script>
<script type='text/javascript' src='http://html.com/wp-content/plugins/table-of-contents-plus/front.min.js?ver=1509'></script>
<script type='text/javascript' src='http://html.com/wp-includes/js/wp-embed.min.js?ver=4.7'></script>

如何将所有 src 属性替换为：

"http://www.example.com/site=PLACEHOLDER&somethingelse"？所以我需要用{上面的 src 网站}

替换 PLACEHOLDER

我找到了可以替换 src link 但不能用替换的 url 本身替换它的代码片段。

怎么做？

Answer 1

假设您的变量中包含源代码，您可以执行以下操作：

$code = "
<script type='text/javascript' src='http://html.com/wp-content/plugins/contact-form-7/includes/js/scripts.js?ver=4.6'></script>
<script type='text/javascript'></script>
<script type='text/javascript' src='http://html.com/wp-content/plugins/table-of-contents-plus/front.min.js?ver=1509'></script>
<script type='text/javascript' src='http://html.com/wp-includes/js/wp-embed.min.js?ver=4.7'></script>";

$pattern = "/src='([^']+)/i";
$replacement = "src='http://www.example.com/site=&somethingelse";

echo preg_replace($pattern, $replacement, $code);

PHP 替换 src link 并保留 url

PHP Replace src link and keep url

php

regex

preg-replace