两次使用相同的命令但如果用户在列表中则得到不同的响应

Question

我目前正在 python 中为 twitch 创建一个机器人。如果用户键入 !start 我想要输出 Tracking time，如果同一用户再次键入 start 我想要输出 Already tracking time。我试过这个：

people = []
if "!start" in message:
    sendMessage(s, "Now recording your time in chat.")
    print(user.title() + " is now tracking time.")
    people.append(user)
    print(", ".join(people))

    if user in people and "start" in message:
        sendMessage(s, "Worked")

当我在聊天中输入“!start”时得到的当前输出是：Tracking time. ~换行~ Already tracking time.

Answer 1

您的问题是您在发送 "Now recording your time in chat" 之后直到案件结束才检查 user 是否已被跟踪。您需要更早地执行该检查。这些方面的内容可能对您有用：

people = []
if "!start" in message:
    if user in people:
        sendMessage(s, "Already tracking time")
    else:
        sendMessage(s, "Now recording your time in chat.")
        print(user.title() + " is now tracking time.")
        people.append(user)
        print(", ".join(people))

不久前在 Python 开发了机器人（编码实践不佳），我猜测这个 if 块是大型 handle_message 函数中的许多块之一。如果是这种情况，您很可能希望将 people = [] 移出该函数，这样它就不会在收到的每条消息上都重新初始化。

使用 sendMessage 的模拟实现来演示此解决方案：

def sendMessage(message):
    print('Bot responds: {}'.format(message))

people = []

def handle_message(user, message):
    print('{} says: {}'.format(user, message))
    if "!start" in message:
        if user in people:
            sendMessage("Already tracking time")
        else:
            sendMessage("Now recording your time in chat.")
            print(user.title() + " is now tracking time.")
            people.append(user)
            print(", ".join(people))

if __name__ == '__main__':
    for _ in range(2):
        handle_message("John", "!start")

输出

John says: !start
Bot responds: Now recording your time in chat.
John is now tracking time.
John
John says: !start
Bot responds: Already tracking time

Answer 2

#people = []
people = {}
if "!start" in message:
    sendMessage(s, "Now recording your time in chat.")
    print(user.title() + " is now tracking time.")
    people[user] = ['Already Tracking Time']
    print(", ".join(people))

    if user in people and "start" in message:
        sendMessage(people[user][0], "Worked") # In case you want to send a different message for different command then you just have to append to the user in this dictionary and reference the correct subscript in the list.

希望这对您有所帮助，否则请提供有关该问题的更多信息和完整代码。

两次使用相同的命令但如果用户在列表中则得到不同的响应

Using the same command twice but getting a differrent response if the user is in the list

python

bots

twitch