XSLT 1.0 使用包含外部参数节点集

Question

我正在尝试将特定节点 (EN_PLAN_NAME) 中的文本与字符串列表进行比较，以便我可以仅输出包含与以下之一匹配的文本的节点那些字符串。我尝试使用这个类似问题的答案：

How to compare against multiple strings in xslt

输入XML

<EligibilityRecords xmlns="http://CDHC_Eligibility_LSDD">
  <Eligibility_Detail_Record xmlns="">
    <EN_PLAN_NAME>Health Savings Account</EN_PLAN_NAME>
    <EN_MBRSHP_EFF_STRT_DT>01012017</EN_MBRSHP_EFF_STRT_DT>
  </Eligibility_Detail_Record>
  <Eligibility_Detail_Record xmlns="">
    <EN_PLAN_NAME>zzHealth Reimbursement Arrangement</EN_PLAN_NAME>
    <EN_MBRSHP_EFF_STRT_DT>01012017</EN_MBRSHP_EFF_STRT_DT>
  </Eligibility_Detail_Record>
  <Eligibility_Detail_Record xmlns="">
    <EN_PLAN_NAME>Health Reimbursement Arrangement 233</EN_PLAN_NAME>
    <EN_MBRSHP_EFF_STRT_DT>01012017</EN_MBRSHP_EFF_STRT_DT>
  </Eligibility_Detail_Record>
  <Eligibility_Detail_Record xmlns="">
    <EN_PLAN_NAME>HRA</EN_PLAN_NAME>
    <EN_MBRSHP_EFF_STRT_DT>01012017</EN_MBRSHP_EFF_STRT_DT>
  </Eligibility_Detail_Record>
  <Eligibility_Detail_Record xmlns="">
    <EN_PLAN_NAME>BASE HRA</EN_PLAN_NAME>
    <EN_MBRSHP_EFF_STRT_DT>01012017</EN_MBRSHP_EFF_STRT_DT>
  </Eligibility_Detail_Record>
  <Eligibility_Detail_Record xmlns="">
    <EN_PLAN_NAME>FSA</EN_PLAN_NAME>
    <EN_MBRSHP_EFF_STRT_DT>01012017</EN_MBRSHP_EFF_STRT_DT>
  </Eligibility_Detail_Record>
</EligibilityRecords>

预期输出XML

<EligibilityRecords xmlns="CDHC_Eligibility_LSDD_Internal">
  <Eligibility_Detail_Record xmlns="">
    <EN_PLAN_NAME>zzHealth Reimbursement Arrangement</EN_PLAN_NAME>
    <EN_MBRSHP_EFF_STRT_DT>01012017</EN_MBRSHP_EFF_STRT_DT>
  </Eligibility_Detail_Record>
  <Eligibility_Detail_Record xmlns="">
    <EN_PLAN_NAME>Health Reimbursement Arrangement 233</EN_PLAN_NAME>
    <EN_MBRSHP_EFF_STRT_DT>01012017</EN_MBRSHP_EFF_STRT_DT>
  </Eligibility_Detail_Record>
  <Eligibility_Detail_Record xmlns="">
    <EN_PLAN_NAME>HRA</EN_PLAN_NAME>
    <EN_MBRSHP_EFF_STRT_DT>01012017</EN_MBRSHP_EFF_STRT_DT>
  </Eligibility_Detail_Record>
  <Eligibility_Detail_Record xmlns="">
    <EN_PLAN_NAME>BASE HRA</EN_PLAN_NAME>
    <EN_MBRSHP_EFF_STRT_DT>01012017</EN_MBRSHP_EFF_STRT_DT>
  </Eligibility_Detail_Record>
</EligibilityRecords>

XSLT

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt"
                xmlns:var="http://schemas.microsoft.com/BizTalk/2003/var"
                exclude-result-prefixes="msxsl var s0 ns0" version="1.0"
                xmlns:s0="CDHC_Eligibility_LSDD"
                xmlns:ns0="CDHC_Eligibility_LSDD_Internal">
  <xsl:output omit-xml-declaration="yes" method="xml" version="1.0" />

  <xsl:param name="HRAPlanNames">
      <PlanName>Health Reimbursement Arrangement</PlanName>
      <PlanName>HRA</PlanName>
  </xsl:param>

  <xsl:template match="@*|node()">
    <xsl:copy>
      <xsl:apply-templates select="@*|node()"/>
    </xsl:copy>
  </xsl:template>

  <xsl:template match="/*">
    <ns0:EligibilityRecords>
      <xsl:for-each select="Eligibility_Detail_Record">
        <xsl:if test="contains(EN_PLAN_NAME,msxsl:node-set($HRAPlanNames)/*)">
          <Eligibility_Detail_Record>
            <xsl:copy-of select="EN_PLAN_NAME"/>
          </Eligibility_Detail_Record>
        </xsl:if>
      </xsl:for-each>
    </ns0:EligibilityRecords>
  </xsl:template>
</xsl:stylesheet>

XSLT 输出任何 EN_PLAN_NAME 的文本包含 "Health Reimbursement Arrangement" 但不输出任何包含 "Health Reimbursement Arrangement" 的节点包含 "HRA"。我不确定我做错了什么。

Answer 1

注意：您可以从两个示例中取出 translate()。在你编辑之前，我已经从你的问题中复制了输入内容。

我现在无法测试 msxsl，但试试这个：

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt"
  xmlns:var="http://schemas.microsoft.com/BizTalk/2003/var"
  exclude-result-prefixes="msxsl var s0 ns0" version="1.0"
  xmlns:s0="CDHC_Eligibility_LSDD"
  xmlns:ns0="CDHC_Eligibility_LSDD_Internal">
  <xsl:output omit-xml-declaration="yes" method="xml" version="1.0" />

  <xsl:param name="HRAPlanNames">
    <PlanName>HEALTH REIMBURSEMENT ARRANGEMENT</PlanName>
    <PlanName>HRA</PlanName>
  </xsl:param>

  <xsl:variable name="lowercase">abcdefghijklmnopqrstuvwxyz</xsl:variable>
  <xsl:variable name="uppercase">ABCDEFGHIJKLMNOPQRSTUVWXYZ</xsl:variable>

  <xsl:template match="/*">
    <xsl:copy>
      <xsl:for-each select="Eligibility_Detail_Record">
        <xsl:variable name="pn" select="translate(EN_PLAN_NAME,$lowercase,$uppercase)"/>
        <xsl:if test="msxsl:node-set($HRAPlanNames)/*[contains($pn,normalize-space())]">
          <Eligibility_Detail_Record>
            <xsl:copy-of select="EN_PLAN_NAME"/>
          </Eligibility_Detail_Record>
        </xsl:if>
      </xsl:for-each>
    </xsl:copy>
  </xsl:template>
</xsl:stylesheet>

如果这不起作用，并且您不介意在 XSLT 中硬编码计划名称（不使用 xsl:param），请尝试不使用 node-set() 的方法：

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt"
  xmlns:var="http://schemas.microsoft.com/BizTalk/2003/var"
  exclude-result-prefixes="msxsl var s0 ns0 local" version="1.0"
  xmlns:s0="CDHC_Eligibility_LSDD"
  xmlns:ns0="CDHC_Eligibility_LSDD_Internal"
  xmlns:local="local">
  <xsl:output omit-xml-declaration="yes" method="xml" version="1.0" />

  <local:HRAPlanNames>
    <local:PlanName>HEALTH REIMBURSEMENT ARRANGEMENT</local:PlanName>
    <local:PlanName>HRA</local:PlanName>
  </local:HRAPlanNames>

  <xsl:variable name="planNames" 
    select="document('')/xsl:stylesheet/local:HRAPlanNames/local:PlanName"/>

  <xsl:variable name="lowercase">abcdefghijklmnopqrstuvwxyz</xsl:variable>
  <xsl:variable name="uppercase">ABCDEFGHIJKLMNOPQRSTUVWXYZ</xsl:variable>

  <xsl:template match="/*">
    <xsl:copy>
      <xsl:for-each select="Eligibility_Detail_Record">
        <xsl:variable name="pn" select="translate(EN_PLAN_NAME,$lowercase,$uppercase)"/>
        <xsl:if test="$planNames[contains($pn,normalize-space())]">
          <Eligibility_Detail_Record>
            <xsl:copy-of select="EN_PLAN_NAME"/>
          </Eligibility_Detail_Record>
        </xsl:if>
      </xsl:for-each>
    </xsl:copy>
  </xsl:template>
</xsl:stylesheet>

Answer 2

contains()函数的两个参数的类型必须是string。您正在尝试将它与 node-set 作为第二个参数一起使用，并且（在 XSLT 1.0 中）这将导致 node-set 中只有第一个节点考虑过。

如果您想保留 HRAPlanNames 参数的当前结构，您需要执行以下操作：

XSLT 1.0

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:msxsl="urn:schemas-microsoft-com:xslt"
exclude-result-prefixes="msxsl" >
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>

<xsl:param name="HRAPlanNames">
      <PlanName>Health Reimbursement Arrangement</PlanName>
      <PlanName>HRA</PlanName>
</xsl:param>

<xsl:template match="/*">
    <EligibilityRecords xmlns="CDHC_Eligibility_LSDD_Internal">
        <xsl:for-each select="Eligibility_Detail_Record">
            <xsl:variable name="plan-name" select="EN_PLAN_NAME" /> 
            <xsl:variable name="test">
                <xsl:for-each select="msxsl:node-set($HRAPlanNames)/PlanName">
                    <xsl:if test="contains($plan-name, .)">Y</xsl:if>
                </xsl:for-each>
            </xsl:variable>
            <xsl:if test="string($test)">
                <xsl:copy-of select="."/>
            </xsl:if>
        </xsl:for-each> 
    </EligibilityRecords>
</xsl:template>

</xsl:stylesheet>

为了得到预期的结果。

XSLT 1.0 使用包含外部参数节点集

XSLT 1.0 Using Contains with External Parameter Node Set

xml

xslt

msxsl

xslt-1.0