Phoenix Ecto - 模型方法中的变量

Question

我正在使用 Phoenix 网络框架 (Elixir) 重写我们现有的基于 python 的 API 交付服务运行成为一个小问题。

我正在尝试创建一个基本的模型方法，当调用它时，您向它传递一个序列号，它通过 Ecto 查询数据库并 returns 结果。查看文档我应该能够使用插值来定义查询中的变量，但我仍然遇到错误。

lib/test_result.ex 文件

defmodule Webservices.TestResult do
  use Ecto.Schema

      schema "test_result" do
            field :date_added, Ecto.DateTime
            field :serial, :string
            field :sequence_id, :integer
            field :last_completed_stage, :integer
            field :last_completed_sequence, :integer
            field :workorder, :string
            field :product, :string
            field :is_complete, :integer
            field :is_scrapped, :integer
            field :value_stream, :string
            field :promise_date, Ecto.Date
            field :fail_lock, :integer
            field :sequence_rev, :integer
            field :date_updated, Ecto.DateTime
            field :date, Ecto.Date
            field :time, Ecto.Time
            field :ptyp2, :string
            field :wo_qty, :integer
            field :is_active, :integer
            field :is_time_lock, :integer
            field :time_lock_timestamp, Ecto.DateTime
            field :scrap_reason, :string
            field :scrapped_by, :integer
      end
  end

lib/test_result_detail.ex 文件

defmodule Webservices.TestResultDetail do
  use Ecto.Schema, :model
  import Ecto.Query

  schema "test_result_detail" do
    field :status_id, :integer
    field :station_id, :integer
    field :stage_id, :integer
    field :operator_id, :integer
    field :failstep, :string
    field :shift, :integer
    field :sequence_rev, :integer
    field :date_added, Ecto.Date
    field :date_timestamp, Ecto.DateTime
    field :date_time, Ecto.Time
    field :stage_order, :integer
    field :serial_number, :string
    field :is_retest, :integer
    field :retest_reason, :string

    has_many :result_id, Webservices.TestResult
end


  def last_completed_test(serial) do
    from c in Webservices.TestResultDetail,
      join: t in TestResult, on: t.id == c.result_id,
      select: {t.serial, c.station_id, c.stage_id, c.operator_id, c.sequence_rev},
      where: t.serial == ^serial,
      order_by: [desc: c.id],
      limit: 1
  end

end

我的控制器：

defmodule Webservices.OPTController do
    use Webservices.Web, :controller

    alias Webservices.Router
    import Webservices.Router.Helpers

    def last(conn, %{"serial" => serial}) do
        import Ecto.Query

        results = Webservices.TestResultDetail.last_completed_test(serial)
        render(conn, "last.json", results: results)

    end
end

我收到以下编译错误：

== Compilation error on file web/controllers/opt_controller.ex == ** (Ecto.Query.CompileError) variable serial is not a valid query expression. Variables need to be explicitly interpolated in queries with ^ expanding macro: Ecto.Query.where/3 web/controllers/opt_controller.ex:12: Webservices.OPTController.index/2 (elixir) expanding macro: Kernel.|>/2 web/controllers/opt_controller.ex:13: Webservices.OPTController.index/2 (elixir) lib/kernel/parallel_compiler.ex:117: anonymous fn/4 in Kernel.ParallelCompiler.spawn_compilers/1

Answer 1

您加入了两个 table，并且在您的 t table 中有 :serial 字段。在 c 中有 :serial_number。只需在 t.serial == ^serial.

上应用此 where 子句

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