Rxjs:重试承诺?
Rxjs: retry a promise?
想知道为什么我的承诺正在解决但正在尝试重试。
var getResultsStream = url => Rx.Observable.onErrorResumeNext(
Rx.Observable.defer( () => Rx.Observable
.fromPromise( getSearchResults(url)
.catch(error => Rx.Observable.of(`Error: ${error}`)) )
.timeout(20000, new Error(`Timeout: ${url}`))
)
.do( e => console.log(`Retrying: ${url}`))
.retry(3)
)
重试承诺 3 次是否更好?
除非您对 defer
and/or 和 onErrorResumeNext
有特殊用途,否则您可以将其全部丢弃并简单地使用:
const request = url => Rx.Observable.of(url)
.do(url => console.log("requesting: " + url))
.switchMap(url => Rx.Observable.fromPromise(getSearchResults(url)))
.timeout(20000, new Error(`Timeout: ${url}`))
.retry(3);
request("http://foobar.com").subscribe(console.log, console.error);
function getSearchResults(url) {
// simulating request-error
throw new Error("Could not reach: " + url);
}
<script src="https://npmcdn.com/@reactivex/rxjs@5.0.0-beta.10/dist/global/Rx.umd.js"></script>
想知道为什么我的承诺正在解决但正在尝试重试。
var getResultsStream = url => Rx.Observable.onErrorResumeNext(
Rx.Observable.defer( () => Rx.Observable
.fromPromise( getSearchResults(url)
.catch(error => Rx.Observable.of(`Error: ${error}`)) )
.timeout(20000, new Error(`Timeout: ${url}`))
)
.do( e => console.log(`Retrying: ${url}`))
.retry(3)
)
重试承诺 3 次是否更好?
除非您对 defer
and/or 和 onErrorResumeNext
有特殊用途,否则您可以将其全部丢弃并简单地使用:
const request = url => Rx.Observable.of(url)
.do(url => console.log("requesting: " + url))
.switchMap(url => Rx.Observable.fromPromise(getSearchResults(url)))
.timeout(20000, new Error(`Timeout: ${url}`))
.retry(3);
request("http://foobar.com").subscribe(console.log, console.error);
function getSearchResults(url) {
// simulating request-error
throw new Error("Could not reach: " + url);
}
<script src="https://npmcdn.com/@reactivex/rxjs@5.0.0-beta.10/dist/global/Rx.umd.js"></script>