Valgrind：在 strcpy 上写入大小 1 无效

Question

该代码试图将大型 uint8_t 数组序列化为二进制字符流。我应该在缓冲区中有足够的空间来复制这些数据；为什么我会收到这些错误？发布的是带有输出错误的完整可运行代码。使用的valgrind命令是：

valgrind --leak-check=yes --track-origins=yes ./prog

主线：

#include "string.h"
#include "stdio.h"
#include "stdlib.h"
#include "stdint.h"
#include <unistd.h>

#define MAX_FRAME_SIZE 9236
#define DAT_LEN 8202

void create_bit_stream(uint8_t frame[], size_t frame_size, char *frame_bits)
{
  /*
   * Takes in uint8_t array of data and converts to binary stream of characters
   * frame        : input array of uint8_t type data
   * frame_size   : size_t length of frame --> sizeof(frame)/sizeof(frame[0])
   * frame_bits   : pointer for returning the character string
   *
   * RETURNS string of binary values generated from input array
  */

  uint8_t tmp[frame_size];
  memset(tmp,0,frame_size);
  memcpy(tmp,frame,frame_size);
  // char bit_string[frame_size*8+1];
  char *bit_string = malloc(frame_size*8+1);
  memset(bit_string,'[=10=]',frame_size*8 + 1);
  for (int i = 0; i < frame_size; i++)
  {
    for (int j = 0; j < 8; j++)
    {
      bit_string[i*8+j] = '0' + (tmp[i] >> 7);
      tmp[i] <<= 1;
    }
  }
  bit_string[frame_size*8] = '[=10=]';
  strcpy(frame_bits, bit_string);
  free(bit_string);
  return;

}

int main(int argc, char *argv[])
{

 char *frame_bits = malloc(MAX_FRAME_SIZE + 1);
 if(!frame_bits)
 {exit(EXIT_FAILURE);}
 memset(frame_bits,'[=10=]',MAX_FRAME_SIZE + 1);

 uint8_t *DAT_frame = malloc(DAT_LEN);
 if(!DAT_frame)
 {exit(EXIT_FAILURE);}
 memset(DAT_frame,0,DAT_LEN);

 //fill with arbitrary data
 for(int i = 0; i < DAT_LEN; i++)
 {
   DAT_frame[i] = i % 255;
 }

 create_bit_stream(DAT_frame, DAT_LEN, frame_bits);

 free(frame_bits); free(DAT_frame);
 return 0;
}

错误：

==2994== Invalid write of size 1
==2994==    at 0x4C31060: strcpy (in /usr/lib/valgrind/vgpreload_memcheck-amd64-linux.so)
==2994==    by 0x40088B: create_bit_stream (stack.c:36)
==2994==    by 0x400993: main (stack.c:61)
==2994==  Address 0x5205455 is 0 bytes after a block of size 9,237 alloc'd
==2994==    at 0x4C2DB8F: malloc (in /usr/lib/valgrind/vgpreload_memcheck-amd64-linux.so)
==2994==    by 0x4008CE: main (stack.c:45)
==2994== 
==2994== Source and destination overlap in strcpy(0x5203040, 0x52074f0)
==2994==    at 0x4C310E6: strcpy (in /usr/lib/valgrind/vgpreload_memcheck-amd64-linux.so)
==2994==    by 0x40088B: create_bit_stream (stack.c:36)
==2994==    by 0x400993: main (stack.c:61)

Answer 1

您的 create_bit_stream 获取字节流并将其扩展为 ASCII-coded 位流。也就是说，如果你给它字节 0x42 ('B') 它会产生 string “01000010”，这是九个字节长（计算终止 nul） .您在为 frame_bits 分配 space 时忘记考虑这一点——不是在 create_bit_stream 中，而是在 main 中：

char *frame_bits = (char *)malloc((MAX_FRAME_SIZE + 1)*sizeof(char));

应该阅读

char *frame_bits = malloc(MAX_FRAME_SIZE * 8 + 1);

(Don't cast the result of malloc.)

（正如我在对该问题的评论中所指出的那样，sizeof(char) == 1 和 sizeof(uint8_t) == 1 根据定义 ；明确地写任何一个都是多余的和错误的代码闻。)

（像这样的 API，调用者提供一个 variable-length 缓冲区，被调用者写入缓冲区，应该始终传递输出缓冲区的大小。您的设计是危险的，原因与 gets 和 sprintf 是危险的。）

Valgrind：在 strcpy 上写入大小 1 无效

Valgrind: Invalid write of size 1 on a strcpy

c

valgrind