Awk in eval - shell 脚本

Question

我需要使用 awk 构建命令，运行使用 eval 命令。我无法获得方法并引用命令。目标是找到端口运行ning 并将带有日期的输出重定向到文件。

#!/bin/bash
curuser=$USER
curworkdir=`pwd`
log_dir="/tmp/logs"
ports_log_file="${log_dir}/netstat_output.log"
ports_not_listening="/tmp/logs/ports_not_listening.out"
echo $log_dir
echo $ports_log_file
if [[ ! -e $ports_log_dir ]]; then
    mkdir -p "$ports_log_dir"
fi
eval "netstat -na | grep [0-9]:80|awk -vabc=$ports_log_file 'BEGIN{"date"|getline d;}/80/{print d,$0 >> abc  }'"
if [ $? -ne 0 ]; then
        echo "error port 80" >> $ports_not_listening
else
        echo "Print success for port-80: $?"    # expected result is 0 exit status
fi
cmd-out=$(netstat -na | grep [0-9]:8080|awk -vabc=$ports_log_file 'BEGIN{"date +'%Y-%m-%d-%r'"|getline d;}/8080/{print d,[=11=] >> abc  }')
if [ "$cmd-out" -ne 0 ]; then
        echo "error port 8080: $cmd_out" >> $ports_not_listening    #expected the return status not 0 for failure
else
        echo "Print success for port-8080: $?" #expected the return status 0 for successful run
fi
## mail the ports that are not listening
if [ -e "${ports_not_listening}" ] ; then
    ## mailx the ports that are not listening, for now just echo to stdout
    echo "$ports_not_listening"
fi
exit 0;

output expected:
2015-01-12-05:38:00 PM tcp        0     0 0.0.0.0:80 0.0.0.0:*                 LISTEN 
2016-01-13-05:39:02 PM tcp        0      0 0.0.0.1:8080              0.0.0.0:*                   LISTEN

任何人都可以验证命令并纠正我如何引用。实现这一目标的正确方法是什么。

Answer 1

为什么不只是

$  netstat -na | 
   awk -v d="$(date)" '/[0-9]:80/ {f=1; print d,[=10=]} 
                       END        {exit f?0:1}' >> $ports_log_file; echo $?

如果任何行匹配设置标志 f，并使用补码作为退出状态。

Awk in eval - shell 脚本

Awk in eval - shell scripting

bash

shell

awk

redirect

eval