Rx – 与超时不同？

Question

我想知道是否有任何方法可以在 .NET 的响应式扩展中实现 Distinct，使其在给定时间内工作，并且在这段时间之后它应该重置并允许再次返回值。我需要这个用于应用程序中的热源，它将工作一整年，现在停止，所以我担心性能，我需要在一段时间后允许这些值。还有 DistinctUntilChanged，但在我的例子中，值可以混合使用——例如：A A X A，DistinctUntilChanged 会给我 A X A，我需要结果 A X，在给定时间后，distinct 应该被重置。

Answer 1

使用包装器 class 为项目添加时间戳，但不考虑用于散列或相等性的时间戳（created 字段）：

public class DistinctForItem<T> : IEquatable<DistinctForItem<T>>
{
    private readonly T item;
    private DateTime created;

    public DistinctForItem(T item)
    {
        this.item = item;
        this.created = DateTime.UtcNow;
    }

    public T Item
    {
        get { return item; }
    }

    public DateTime Created
    {
        get { return created; }
    }

    public bool Equals(DistinctForItem<T> other)
    {
        if (ReferenceEquals(null, other)) return false;
        if (ReferenceEquals(this, other)) return true;
        return EqualityComparer<T>.Default.Equals(Item, other.Item);
    }

    public override bool Equals(object obj)
    {
        if (ReferenceEquals(null, obj)) return false;
        if (ReferenceEquals(this, obj)) return true;
        if (obj.GetType() != this.GetType()) return false;
        return Equals((DistinctForItem<T>)obj);
    }

    public override int GetHashCode()
    {
        return EqualityComparer<T>.Default.GetHashCode(Item);
    }

    public static bool operator ==(DistinctForItem<T> left, DistinctForItem<T> right)
    {
        return Equals(left, right);
    }

    public static bool operator !=(DistinctForItem<T> left, DistinctForItem<T> right)
    {
        return !Equals(left, right);
    }
}

现在可以编写 DistinctFor 扩展方法：

public static IObservable<T> DistinctFor<T>(this IObservable<T> src, 
                                            TimeSpan validityPeriod)
{
    //if HashSet<DistinctForItem<T>> actually allowed us the get at the 
    //items it contains it would be a better choice. 
    //However it doesn't, so we resort to 
    //Dictionary<DistinctForItem<T>, DistinctForItem<T>> instead.

    var hs = new Dictionary<DistinctForItem<T>, DistinctForItem<T>>();
    return src.Select(item => new DistinctForItem<T>(item)).Where(df =>
    {
        DistinctForItem<T> hsVal;
        if (hs.TryGetValue(df, out hsVal))
        {
            var age = DateTime.UtcNow - hsVal.Created;
            if (age < validityPeriod)
            {
                return false;
            }
        }
        hs[df] = df;
        return true;

    }).Select(df => df.Item);
}

可以使用的：

Enumerable.Range(0, 1000)
    .Select(i => i % 3)
    .ToObservable()
    .Pace(TimeSpan.FromMilliseconds(500)) //drip feeds the observable
    .DistinctFor(TimeSpan.FromSeconds(5))
    .Subscribe(x => Console.WriteLine(x));

作为参考，这是我对 Pace<T>:

的实现

public static IObservable<T> Pace<T>(this IObservable<T> src, TimeSpan delay)
{
    var timer = Observable
        .Timer(
            TimeSpan.FromSeconds(0),
            delay
        );

    return src.Zip(timer, (s, t) => s);
}

Answer 2

接受的答案有缺陷；缺陷如下所示。这是解决方案的演示，带有测试批次：

TestScheduler ts = new TestScheduler();

var source = ts.CreateHotObservable<char>(
    new Recorded<Notification<char>>(200.MsTicks(), Notification.CreateOnNext('A')),
    new Recorded<Notification<char>>(300.MsTicks(), Notification.CreateOnNext('B')),
    new Recorded<Notification<char>>(400.MsTicks(), Notification.CreateOnNext('A')),
    new Recorded<Notification<char>>(500.MsTicks(), Notification.CreateOnNext('A')),
    new Recorded<Notification<char>>(510.MsTicks(), Notification.CreateOnNext('C')),
    new Recorded<Notification<char>>(550.MsTicks(), Notification.CreateOnNext('B')),
    new Recorded<Notification<char>>(610.MsTicks(), Notification.CreateOnNext('B'))
);

var target = source.TimedDistinct(TimeSpan.FromMilliseconds(300), ts);

var expectedResults = ts.CreateHotObservable<char>(
    new Recorded<Notification<char>>(200.MsTicks(), Notification.CreateOnNext('A')),
    new Recorded<Notification<char>>(300.MsTicks(), Notification.CreateOnNext('B')),
    new Recorded<Notification<char>>(500.MsTicks(), Notification.CreateOnNext('A')),
    new Recorded<Notification<char>>(510.MsTicks(), Notification.CreateOnNext('C')),
    new Recorded<Notification<char>>(610.MsTicks(), Notification.CreateOnNext('B'))
);

var observer = ts.CreateObserver<char>();
target.Subscribe(observer);
ts.Start();

ReactiveAssert.AreElementsEqual(expectedResults.Messages, observer.Messages);

解决方案包括 TimedDistinct 的一些重载，允许 IScheduler 注入，以及 IEqualityComparer<T> 注入，类似于 Distinct。忽略所有这些重载，解决方案依赖于辅助方法 StateWhere，它有点像 Scan 和 Where 的组合：它像 Where 一样过滤，但允许您可以像 Scan 一样在其中嵌入状态。

public static class RxState
{
    public static IObservable<TSource> TimedDistinct<TSource>(this IObservable<TSource> source, TimeSpan expirationTime)
    {
        return TimedDistinct(source, expirationTime, Scheduler.Default);    
    }

    public static IObservable<TSource> TimedDistinct<TSource>(this IObservable<TSource> source, TimeSpan expirationTime, IScheduler scheduler)
    {
        return TimedDistinct<TSource>(source, expirationTime, EqualityComparer<TSource>.Default, scheduler);
    }

    public static IObservable<TSource> TimedDistinct<TSource>(this IObservable<TSource> source, TimeSpan expirationTime, IEqualityComparer<TSource> comparer)
    {
        return TimedDistinct(source, expirationTime, comparer, Scheduler.Default);
    }

    public static IObservable<TSource> TimedDistinct<TSource>(this IObservable<TSource> source, TimeSpan expirationTime, IEqualityComparer<TSource> comparer, IScheduler scheduler)
    {
        var toReturn = source
            .Timestamp(scheduler)
            .StateWhere(
                new Dictionary<TSource, DateTimeOffset>(comparer),
                (state, item) => item.Value,
                (state, item) => state
                    .Where(kvp => item.Timestamp - kvp.Value < expirationTime)
                    .Concat( 
                        !state.ContainsKey(item.Value) || item.Timestamp - state[item.Value] >= expirationTime
                            ? Enumerable.Repeat(new KeyValuePair<TSource, DateTimeOffset>(item.Value, item.Timestamp), 1)
                            : Enumerable.Empty<KeyValuePair<TSource, DateTimeOffset>>()
                    )
                    .ToDictionary(kvp => kvp.Key, kvp => kvp.Value, comparer),
                (state, item) => !state.ContainsKey(item.Value) || item.Timestamp - state[item.Value] >= expirationTime
        );
        return toReturn;
    }

    public static IObservable<TResult> StateSelectMany<TSource, TState, TResult>(
            this IObservable<TSource> source,
            TState initialState,
            Func<TState, TSource, IObservable<TResult>> resultSelector,
            Func<TState, TSource, TState> stateSelector
        )
    {
        return source
            .Scan(Tuple.Create(initialState, Observable.Empty<TResult>()), (state, item) => Tuple.Create(stateSelector(state.Item1, item), resultSelector(state.Item1, item)))
            .SelectMany(t => t.Item2);
    }

    public static IObservable<TResult> StateWhere<TSource, TState, TResult>(
            this IObservable<TSource> source,
            TState initialState,
            Func<TState, TSource, TResult> resultSelector,
            Func<TState, TSource, TState> stateSelector,
            Func<TState, TSource, bool> filter
        )
    {
        return source
            .StateSelectMany(initialState, (state, item) =>
                    filter(state, item) ? Observable.Return(resultSelector(state, item)) : Observable.Empty<TResult>(),
                stateSelector);
    }
}

接受的答案有两个缺陷：

它不接受 IScheduler 注入，这意味着很难在 Rx 测试框架内进行测试。这很容易修复。
它依赖于可变状态，这在像 Rx 这样的多线程框架中不能很好地工作。

问题 #2 对于多个订阅者很明显：

var observable = Observable.Range(0, 5)
    .DistinctFor(TimeSpan.MaxValue)
    ;

observable.Subscribe(i => Console.WriteLine(i));
observable.Subscribe(i => Console.WriteLine(i));

按照常规的 Rx 行为，输出应该输出 0-4 两次。相反，0-4 只输出一次。

这是另一个示例缺陷：

var subject = new Subject<int>();
var observable = subject
    .DistinctFor(TimeSpan.MaxValue);

observable.Subscribe(i => Console.WriteLine(i));
observable.Subscribe(i => Console.WriteLine(i));

subject.OnNext(1);
subject.OnNext(2);
subject.OnNext(3);

这会输出 1 2 3 一次，而不是两次。

这是 MsTicks 的代码：

public static class RxTestingHelpers
{
    public static long MsTicks(this int ms)
    {
        return TimeSpan.FromMilliseconds(ms).Ticks;
    }

}

Rx – 与超时不同？

Rx – Distinct with timeout?

.net

c#

timeout

distinct

system.reactive