多对多关系中的条件分离 laravel

Question

我有2个模型Tour.php

public function includes()
{
    return $this->belongsToMany('App\Included');
}

Included.php

public function tours()
{
    return $this->belongsToMany('App\Tour');
}

如果 tour 中有 includeds，我正在尝试分离 includeds，同时删除游览。

下面的代码是我试过的：

    public function destroy($id)
{
    $tour = Tour::find($id);

    if ($test = $tour->includeds()->count() != null) {
        $tour->includeds()->detach();
    }
    if ($test = $tour->excludeds()->count() != null) {
        $tour->excludeds()->detach();
    }        
    $tour->delete();

    Session::flash('success', 'The tour is sucessfully deleted.');
    return redirect()->route('tours.index');
}

以上代码生成 Call to undefined method Illuminate\Database\Query\Builder::includeds() 错误。请指出我犯的错误。

Answer 1

小错别字

试试下面的代码

 public function destroy($id)
  {
    $tour = Tour::find($id);

    if ($test = $tour->includes()->count() != null) {
        $tour->includes()->detach();
    }
    if ($test = $tour->excludeds()->count() != null) {
        $tour->excludeds()->detach();
    }        
    $tour->delete();

    Session::flash('success', 'The tour is successfully deleted.');
    return redirect()->route('tours.index');
}

多对多关系中的条件分离 laravel

Conditional detach in many to many relationship laravel

php

laravel

laravel-5.3