返回记录数，不考虑 Limit cakePHP 3

Question

我想要当前查询的数据库中可用的记录数，但不考虑 LIMIT。

$this->Orders->find('all')
             ->where(['order_quantity']=>5)
             ->LIMIT(5);

考虑一下，对于上述查询，我有 50 条记录。所以只想要当前查询可用的记录数。我不能使用 'count()' 因为限制它总是 return 可用记录总数小于或等于 5。cakePHP 中有任何解决方案吗？

Answer 1

我认为您不熟悉 find 中 limit 的使用。所以，我建议你研究docs.

您的查询中的限制意味着即使查询实际有 50 条数据，该查询也只会显示前 5 条数据。

因此，为了获得实际数据，您只需取消限制并在代码中进行一些更改，如下所示：

$this->Orders->find('count')->where(['order_quantity' => 5]);

Answer 2

This page in the CakePHP 3 book，准确解释您的问题的答案，包括其工作原理和原因：

Returning the Total Count of Records

Using a single query object, it is possible to obtain the total number of rows found for a set of conditions:
$total = $articles->find()->where(['is_active' => true])->count();
The count() method will ignore the limit, offset and page clauses, thus the following will return the same result:
$total = $articles->find()->where(['is_active' => true])->limit(10)->count();
This is useful when you need to know the total result set size in advance, without having to construct another Query object. Likewise, all result formatting and map-reduce routines are ignored when using the count() method.

注意关于“...将忽略限制、偏移和页面子句”的内容

所以尝试这样的事情：

$data = $articles->find()->where(['is_active' => true])->limit(10);
$count = $data->count();

返回记录数，不考虑 Limit cakePHP 3

Count of no of record returned, without considering Limit cakePHP 3

pagination

cakephp

cakephp-3.x