ReplyToId' 不能为空
ReplyToId' cannot be null
这个异常一直在抛。这是从我将 botframework 更新到 3.5.3 开始的。
代码:
消息控制器:
await Conversation.SendAsync(activity, () => new DefaultDialog());
比在我的 DefaultDialog 中:
private async Task MessageReceivedAsync(IDialogContext context, IAwaitable<IMessageActivity> argument)
{
var msg = await argument;
await Helper.CallMenu(context, msg);
在 CallMenu 函数中:
internal static async Task CallMenu(IDialogContext context, IMessageActivity msg)
{
await MenuFirstPart(context, msg);
在 MenuFirstPart 函数中:
internal static async Task MenuFirstPart(IDialogContext context, IMessageActivity msg)
{
await context.PostAsync("I can assist you with : ");
msg.AttachmentLayout = AttachmentLayoutTypes.Carousel;
msg.Attachments = new List<Attachment>();
ThumbnailCard thumbnailCard = new ThumbnailCard()
{
Buttons = new List<CardAction>
{
new CardAction ()
{
Value = "Method_News",
Type = "postBack",
Title = "News"
},
new CardAction()
{
Value = "Method_About",
Type = "postBack",
Title = "About"
},
new CardAction ()
{
Value = "Method_Help",
Type = "postBack",
Title = "Help"
},
},
};
msg.Attachments.Add(thumbnailCard.ToAttachment());
await context.PostAsync(msg);
}
上下文尝试 post msg.
时抛出异常
有什么帮助吗?或者如何将我的机器人降级到 3.5.0。这在那里工作得很好......
您正在使用传入消息 (msg
) 并将其发回。
您需要创建一条新消息。使用以下内容:
var reply = context.MakeMessage();
这个异常一直在抛。这是从我将 botframework 更新到 3.5.3 开始的。
代码:
消息控制器:
await Conversation.SendAsync(activity, () => new DefaultDialog());
比在我的 DefaultDialog 中:
private async Task MessageReceivedAsync(IDialogContext context, IAwaitable<IMessageActivity> argument)
{
var msg = await argument;
await Helper.CallMenu(context, msg);
在 CallMenu 函数中:
internal static async Task CallMenu(IDialogContext context, IMessageActivity msg)
{
await MenuFirstPart(context, msg);
在 MenuFirstPart 函数中:
internal static async Task MenuFirstPart(IDialogContext context, IMessageActivity msg)
{
await context.PostAsync("I can assist you with : ");
msg.AttachmentLayout = AttachmentLayoutTypes.Carousel;
msg.Attachments = new List<Attachment>();
ThumbnailCard thumbnailCard = new ThumbnailCard()
{
Buttons = new List<CardAction>
{
new CardAction ()
{
Value = "Method_News",
Type = "postBack",
Title = "News"
},
new CardAction()
{
Value = "Method_About",
Type = "postBack",
Title = "About"
},
new CardAction ()
{
Value = "Method_Help",
Type = "postBack",
Title = "Help"
},
},
};
msg.Attachments.Add(thumbnailCard.ToAttachment());
await context.PostAsync(msg);
}
上下文尝试 post msg.
时抛出异常有什么帮助吗?或者如何将我的机器人降级到 3.5.0。这在那里工作得很好......
您正在使用传入消息 (msg
) 并将其发回。
您需要创建一条新消息。使用以下内容:
var reply = context.MakeMessage();