PL/SQL 用表中的数据填充对象

Question

我在 pl/sql 中创建了自定义对象。我想要做的是创建从 table 传递 id 的对象，并用一行中的数据填充对象属性（由此 id 指定）。这个怎么做？我在 oracle 10g 中工作。

我的类型是这样的：

CREATE OR REPLACE TYPE userType AS OBJECT(
    id number,
    name varchar2(100),
    nickname varchar2(100),
    email varchar2(100),
    CONSTRUCTOR FUNCTION userType(userId number) RETURN SELF AS RESULT
);

和type body声明：

CREATE OR REPLACE TYPE BODY userType AS
    CONSTRUCTOR FUNCTION userType(userId number) RETURN SELF AS RESULT
    AS
    BEGIN
        self.id := userId;
        self.name := ???;    --<- need help there  
        self.nickname := ??? --(something like select name from userType where id = userId)                   
        (and so on)
        RETURN;
    END;
END;

Table 列与 userType 个属性同名。

Answer 1

我认为您应该能够做到以下几点：

CREATE OR REPLACE TYPE BODY userType AS
    CONSTRUCTOR FUNCTION userType(userId number) RETURN SELF AS RESULT
    AS
    BEGIN
        self.id := userId;
        SELECT name, nickname INTO self.name, self.nickname FROM user_table WHERE id = userId;                   
        RETURN;
    END;
END;

虽然我不确定这是正确的还是最好的方法。

Answer 2

我认为你正在尝试这样做

SQL> desc employ
 Name                                      Null?    Type
 ----------------------------------------- -------- ---------------------------

 ID                                                 NUMBER
 NAME                                               VARCHAR2(50)


SQL> select * from employ
  2  ;

        ID NAME
---------- --------------------------------------------------
         1 Exhaust
         2 Object
         3 Fill



SQL> ed
Wrote file afiedt.buf

  1  create or replace type usertype as object
  2  (
  3  id number,
  4  name varchar2(50),
  5  constructor function usertype(userId number) return self as result
  6* );
SQL> /

Type created.


SQL> ed
Wrote file afiedt.buf

  1  create or replace type body usertype as
  2  constructor function usertype(userid number) return self as result
  3  as
  4  outvar employ.name%type;
  5  begin
  6  self.id := userid;
  7  select name into outvar from employ where id = userid;
  8  self.name := outvar;
  9  return;
 10  end;
 11* end;
SQL> /

Type body created.



SQL> declare
  2  v_usertype usertype;
  3  begin
  4  v_usertype := usertype(1);
  5  dbms_output.put_line(v_usertype.name);
  6  end;
  7  /
Exhaust

PL/SQL procedure successfully completed.

PL/SQL 用表中的数据填充对象

PL/SQL Fill object with data from tables

database

oracle

constructor

plsql

object-type