创建通用插入函数
Creating Generic Insert function
我正在尝试创建可以采用 table 名称和值并将 return 插入到查询中的通用函数,并想出了如下所示的内容:
struct any {
enum type {Int, Float, String};
any(int e) { m_data.INT = e; m_type = Int;}
any(float e) { m_data.FLOAT = e; m_type = Float;}
any(char* e) { m_data.STRING = e; m_type = String;}
type get_type() const { return m_type; }
int get_int() const { return m_data.INT; }
float get_float() const { return m_data.FLOAT; }
char* get_string() const { return m_data.STRING; }
private:
type m_type;
union {
int INT;
float FLOAT;
char *STRING;
} m_data;
};
template<typename ...Args>
std::string GetInsertString(const std::string& tableName, Args... args)
{
std::string insertString = "INSERT INTO ";
insertString += tableName;
insertString += " VALUES(";
std::vector<any> vec = {args...};
std::ostringstream ss;
for (unsigned i = 0; i < vec.size(); ++i)
{
switch(vec[i].get_type())
{
case any::Int:
ss.str("");
ss << vec[i].get_int();
insertString += ss.str() + ",";
break;
case any::Float:
ss.str("");
ss << vec[i].get_float();
insertString += ss.str() + ",";
break;
case any::String:
ss.str("");
insertString += "'" + std::string(vec[i].get_string()) + "'," ;
break;
}
}
insertString.pop_back();
insertString += ");";
return insertString;
}
其中 any 是 class 基于此 link How can I iterate over a packed variadic template argument list?
但问题是我无法将 std::string
类型作为可变参数传递给此函数,因为我们在 any class 中有联合,所以需要帮助你们将 std::string
类型作为参数传递给插入查询
typeof
您可以使用 typeof
并添加开关盒。例如,在新的 java 中,如果我没记错的话,您可以自动执行一个半循环并同样将其视为某种循环。
您可以使用虚拟基础 class、模板包装器和智能指针,如下所示
#include <string>
#include <vector>
#include <memory>
#include <sstream>
#include <iostream>
struct anyBase
{ virtual int unusedVirt () { return 0; }; };
template <typename T>
struct anyW : public anyBase
{
T val;
anyW (T const & v0) : val{v0} { }
};
struct any
{
public:
enum type { Int, Float, String };
any (int e)
: m_type{Int}, m_data{new anyW<int>(e)} { }
any (float e)
: m_type{Float}, m_data{new anyW<float>(e)} { }
any (char const * e)
: m_type{String}, m_data{new anyW<std::string>(e)} { }
any (std::string const & e)
: m_type{String}, m_data{new anyW<std::string>(e)} { }
any (any const & a) : m_type{a.m_type}, m_data{nullptr}
{
switch ( m_type )
{
case Int:
m_data.reset(new anyW<int>(a.get_int()));
break;
case Float:
m_data.reset(new anyW<float>(a.get_float()));
break;
case String:
m_data.reset(new anyW<std::string>(a.get_string()));
break;
}
}
type get_type () const { return m_type; }
int get_int () const
{ return dynamic_cast<anyW<int>*>(m_data.get())->val; }
float get_float () const
{ return dynamic_cast<anyW<float>*>(m_data.get())->val; }
std::string const & get_string () const
{ return dynamic_cast<anyW<std::string>*>(m_data.get())->val; }
private:
type m_type;
std::unique_ptr<anyBase> m_data;
};
template<typename ...Args>
std::string GetInsertString(const std::string& tableName, Args... args)
{
std::string insertString = "INSERT INTO ";
insertString += tableName;
insertString += " VALUES(";
std::vector<any> vec = {args...};
std::ostringstream ss;
for (unsigned i = 0; i < vec.size(); ++i)
{
switch(vec[i].get_type())
{
case any::Int:
ss.str("");
ss << vec[i].get_int();
insertString += ss.str() + ",";
break;
case any::Float:
ss.str("");
ss << vec[i].get_float();
insertString += ss.str() + ",";
break;
case any::String:
ss.str("");
insertString += "'" + std::string(vec[i].get_string()) + "'," ;
break;
}
}
insertString.pop_back();
insertString += ");";
return insertString;
}
int main ()
{
std::cout << GetInsertString("fooTable", 1, 2.2f, "3", std::string("4"))
<< std:: endl;
// print INSERT INTO fooTable VALUES(1,2.2,'3','4');
}
注意:
此解决方案也适用于 C++11
我统一了 char *
和 std::string
的情况;我认为注册一个 chat *
是个坏主意
使用 std::unique_ptr
你需要 copy_constructor 因为 std::unique_ptr
中的复制构造函数被删除所以也删除了任何默认的复制构造函数
更好的解决方案可能是等待传入(C++17,如果我没记错的话)std::variant
我正在尝试创建可以采用 table 名称和值并将 return 插入到查询中的通用函数,并想出了如下所示的内容:
struct any {
enum type {Int, Float, String};
any(int e) { m_data.INT = e; m_type = Int;}
any(float e) { m_data.FLOAT = e; m_type = Float;}
any(char* e) { m_data.STRING = e; m_type = String;}
type get_type() const { return m_type; }
int get_int() const { return m_data.INT; }
float get_float() const { return m_data.FLOAT; }
char* get_string() const { return m_data.STRING; }
private:
type m_type;
union {
int INT;
float FLOAT;
char *STRING;
} m_data;
};
template<typename ...Args>
std::string GetInsertString(const std::string& tableName, Args... args)
{
std::string insertString = "INSERT INTO ";
insertString += tableName;
insertString += " VALUES(";
std::vector<any> vec = {args...};
std::ostringstream ss;
for (unsigned i = 0; i < vec.size(); ++i)
{
switch(vec[i].get_type())
{
case any::Int:
ss.str("");
ss << vec[i].get_int();
insertString += ss.str() + ",";
break;
case any::Float:
ss.str("");
ss << vec[i].get_float();
insertString += ss.str() + ",";
break;
case any::String:
ss.str("");
insertString += "'" + std::string(vec[i].get_string()) + "'," ;
break;
}
}
insertString.pop_back();
insertString += ");";
return insertString;
}
其中 any 是 class 基于此 link How can I iterate over a packed variadic template argument list?
但问题是我无法将 std::string
类型作为可变参数传递给此函数,因为我们在 any class 中有联合,所以需要帮助你们将 std::string
类型作为参数传递给插入查询
typeof
您可以使用 typeof
并添加开关盒。例如,在新的 java 中,如果我没记错的话,您可以自动执行一个半循环并同样将其视为某种循环。
您可以使用虚拟基础 class、模板包装器和智能指针,如下所示
#include <string>
#include <vector>
#include <memory>
#include <sstream>
#include <iostream>
struct anyBase
{ virtual int unusedVirt () { return 0; }; };
template <typename T>
struct anyW : public anyBase
{
T val;
anyW (T const & v0) : val{v0} { }
};
struct any
{
public:
enum type { Int, Float, String };
any (int e)
: m_type{Int}, m_data{new anyW<int>(e)} { }
any (float e)
: m_type{Float}, m_data{new anyW<float>(e)} { }
any (char const * e)
: m_type{String}, m_data{new anyW<std::string>(e)} { }
any (std::string const & e)
: m_type{String}, m_data{new anyW<std::string>(e)} { }
any (any const & a) : m_type{a.m_type}, m_data{nullptr}
{
switch ( m_type )
{
case Int:
m_data.reset(new anyW<int>(a.get_int()));
break;
case Float:
m_data.reset(new anyW<float>(a.get_float()));
break;
case String:
m_data.reset(new anyW<std::string>(a.get_string()));
break;
}
}
type get_type () const { return m_type; }
int get_int () const
{ return dynamic_cast<anyW<int>*>(m_data.get())->val; }
float get_float () const
{ return dynamic_cast<anyW<float>*>(m_data.get())->val; }
std::string const & get_string () const
{ return dynamic_cast<anyW<std::string>*>(m_data.get())->val; }
private:
type m_type;
std::unique_ptr<anyBase> m_data;
};
template<typename ...Args>
std::string GetInsertString(const std::string& tableName, Args... args)
{
std::string insertString = "INSERT INTO ";
insertString += tableName;
insertString += " VALUES(";
std::vector<any> vec = {args...};
std::ostringstream ss;
for (unsigned i = 0; i < vec.size(); ++i)
{
switch(vec[i].get_type())
{
case any::Int:
ss.str("");
ss << vec[i].get_int();
insertString += ss.str() + ",";
break;
case any::Float:
ss.str("");
ss << vec[i].get_float();
insertString += ss.str() + ",";
break;
case any::String:
ss.str("");
insertString += "'" + std::string(vec[i].get_string()) + "'," ;
break;
}
}
insertString.pop_back();
insertString += ");";
return insertString;
}
int main ()
{
std::cout << GetInsertString("fooTable", 1, 2.2f, "3", std::string("4"))
<< std:: endl;
// print INSERT INTO fooTable VALUES(1,2.2,'3','4');
}
注意:
此解决方案也适用于 C++11
我统一了
char *
和std::string
的情况;我认为注册一个chat *
是个坏主意
使用
std::unique_ptr
你需要 copy_constructor 因为std::unique_ptr
中的复制构造函数被删除所以也删除了任何默认的复制构造函数更好的解决方案可能是等待传入(C++17,如果我没记错的话)
std::variant