如何在 Android 上检查用户是否在运行时授予了权限?

How to check if permission is granted by user at runtime on Android?

我创建了一个简单的 android activity 作为表盘。 它有 phone 号码的编辑文本和呼叫按钮 这是代码:(android 6.0 棉花糖)

public class Main2Activity extends AppCompatActivity {
EditText num;
Button call;
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main2);
    num = (EditText) findViewById(R.id.num);
    call = (Button) findViewById(R.id.call);
    call.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            try {
                // request permission if not granted
                if (ActivityCompat.checkSelfPermission(Main2Activity.this, Manifest.permission.CALL_PHONE) != PackageManager.PERMISSION_GRANTED) {
                    ActivityCompat.requestPermissions(Main2Activity.this, new String[]{Manifest.permission.CALL_PHONE}, 123);
                    // i suppose that the user has granted the permission
                    Intent in = new Intent(Intent.ACTION_CALL, Uri.parse("tel:" + num.getText().toString()));
                    startActivity(in);
                 // if the permission is granted then ok
                } else {
                    Intent in = new Intent(Intent.ACTION_CALL, Uri.parse("tel:" + num.getText().toString()));
                    startActivity(in);
                }
            }
            // catch the exception if I try to make a call and the permission is not granted
            catch (Exception e){
            }
        }
    });
}

}

当我 运行 我的应用程序时,我遇到了这些问题

使用onRequestPermissionResult,如果用户按下ALLOWDENY,它会处理动作,只需在条件[=19=中调用意图]:

@Override
    public void onRequestPermissionsResult(int requestCode, String permissions[], int[] grantResults) {
        super.onRequestPermissionsResult(requestCode, permissions, grantResults);
        switch (requestCode) {
            case 123: {
                if (grantResults.length > 0
                        && grantResults[0] == PackageManager.PERMISSION_GRANTED) {
                   //If user presses allow
                   Toast.makeText(Main2Activity.this, "Permission granted!", Toast.LENGTH_SHORT).show();
                   Intent in = new Intent(Intent.ACTION_CALL, Uri.parse("tel:" + num.getText().toString()));
                startActivity(in);
                } else {
                   //If user presses deny
                   Toast.makeText(Main2Activity.this, "Permission denied", Toast.LENGTH_SHORT).show();
                }
                break;
            }
        }
    }

希望对您有所帮助。

if (grantResults.length > 0 && grantResults[0] == PackageManager.PERMISSION_GRANTED)检查权限结果的逻辑很糟糕,我不知道为什么Google实现了这么糟糕的代码。

这是一团糟,尤其是当您检查多个权限时。假设你要求 CAMERAACCESS_FINE_LOCATIONACCESS_NETWORK_STATE

您需要检查 ACCESS_FINE_LOCATION 但用户最初只授予 CAMERA 运行 然后您检查 grantResults[1] 但在第二个 运行 ACCESS_FINE_LOCATION 成为索引 0 的权限。用户没有立即授予所有权限,我遇到了很多问题。

您应该使用

   int size = permissions.length;
    boolean locationPermissionGranted = false;

    for (int i = 0; i < size; i++) {
        if (permissions[i].equals(Manifest.permission.ACCESS_FINE_LOCATION)
                && grantResults[i] == PackageManager.PERMISSION_GRANTED) {
            locationPermissionGranted = true;
        }
    }

或更简单的

   if (ContextCompat.checkSelfPermission(this, Manifest.permission.ACCESS_FINE_LOCATION)
                == PackageManager.PERMISSION_GRANTED) {
           // Do something ...
        }

onPermissionRequestResult 方法中。