仅显示创建者的文件 - Django/Python

Question

我想只显示创作者（用户）上传的图片到他们的个人资料中。

我该如何修改我的代码来显示它？

谢谢！

models.py:

class Photo(models.Model):
    creator = models.ForeignKey(MyUser, null=False, blank=False)
    category = models.ForeignKey("Category", default=1, null=True, blank=True)
    title = models.CharField(max_length=30, null=True, blank=True)
    description = models.TextField(max_length=120, null=True, blank=True)
    image = models.ImageField(upload_to='user/photos/', null=True, blank=True)
    slug = models.SlugField(null=False, blank=False)
    active = models.BooleanField(default=True)
    timestamp = models.DateTimeField(auto_now_add=True, auto_now=False, null=True)
    updated = models.DateTimeField(auto_now_add=False, auto_now=True, null=True)

    class Meta:
        unique_together = ('slug', 'category')
        ordering = ['-timestamp']

    def __unicode__(self):
        return "%s" %(self.creator)

    def get_image_url(self):
        return "%s/%s" %(settings.MEDIA_URL, self.image)

    def get_absolute_url(self):
        return "%s/%s" %(self.creator, self.slug)

views.py:

@login_required
def account_home(request, username):
    try:
        u = MyUser.objects.get(username=username)
    except:
        u = None
    photo_set = Photo.objects.all()
    context = {
        "photo_set": photo_set,
        "notifications": notifications,
        "transactions": transactions
    }

    return render(request, "accounts/account_home.html", context)

.html:

{% for photo in photo_set %}
    <a href="{{ photo.get_absolute_url }}"><img src="{{ photo.get_image_url }}" class='img-responsive'></a>
    <hr/>
{% endfor %}

Answer 1

你有一个用户的外键，所以你可以通过它来过滤照片：

photo_set = Photo.objects.filter(creator=u)

或者更好地使用反向关系：

photo_set = u.photo_set.all()

此外，永远不要在代码中使用空白的 except 语句。您期望 get 引发的唯一异常是 MyUser.DoesNotExist，因此您应该只捕获它。

仅显示创建者的文件 - Django/Python

Display only creator's files - Django/Python

html

python

django

django-models

django-views