$(".class").val() 返回未定义的值
$(".class").val() is returning undefined value
我正在连接到 Trello API 并使用看板中的列表创建一个。然后我试图列出每个列表中的所有卡片。从 value 属性获取 ListID 时,它返回 "undefined"。这是为什么?
我用 document.getElementById("demo").innerHTML = $(".board").val();
打印出来
//HTML
<label>Choose from a List of Boards</label>
<div id="output"></div>
<label>Display Cards Below for Board Selected</label>
<div id="outputCards"></div>
<p id="demo"></p>
//Javascript
var $boards = $("<select>")
.attr("id", "boards")
.text("Loading Boards...")
.appendTo("#output");
Trello.get("/boards/BOARD_ID/lists", function(boards) {
$boards.empty();
$.each(boards, function(ix, board) {
$("<option>")
.attr({href: board.url, target: "trello", value : board.id, name : board.id, id : board.id})
.addClass("board")
.text(board.name)
.appendTo($boards);
});
});
var $cards = $("<div>")
.text("Loading Cards...")
.appendTo("#outputCards")
.appendTo("#demo");
// This is where I'm trying to return the value
document.getElementById("demo").innerHTML = $(".board").val();
var resource = "lists/LIST_ID/cards";
Trello.get(resource, function(cards) {
$cards.empty();
$.each(cards, function(ix, card) {
$("<a>")
.attr({href: card.url, target: "trello"})
.addClass("card")
.text(card.name)
.appendTo($cards);
});
});
HTML 输出如下:
<label>Choose from a List of Boards</label>
<div id="output">
<select id="boards">
<option target="trello" value="LIST_ID" name="LIST_ID" id="LIST_ID" class="board">
List One
</option>
...
</select>
</div>
<label>Display Cards Below for Board Selected</label>
<div id="outputCards"></div>
<p id="demo">undefined</p>
我认为这里的主要问题是 board
class 仅被添加到 Trello.get
回调中的元素。
由于此代码是异步执行的,因此您很可能在执行回调中的代码之前 $(".board").val()
,这意味着 `$(".board") 未返回任何元素。
我会考虑这样的事情
Trello.get("/boards/BOARD_ID/lists", function(boards) {
$boards.empty();
$.each(boards, function(ix, board) {
$("<option>")
.attr({href: board.url, target: "trello", value : board.id, name : board.id, id : board.id})
.addClass("board")
.text(board.name)
.appendTo($boards);
});
// This is where I'm trying to return the value
$('#board').change(function () {
document.getElementById("demo").innerHTML = $(".board:selected").val();
});
});
我正在连接到 Trello API 并使用看板中的列表创建一个。然后我试图列出每个列表中的所有卡片。从 value 属性获取 ListID 时,它返回 "undefined"。这是为什么?
我用 document.getElementById("demo").innerHTML = $(".board").val();
//HTML
<label>Choose from a List of Boards</label>
<div id="output"></div>
<label>Display Cards Below for Board Selected</label>
<div id="outputCards"></div>
<p id="demo"></p>
//Javascript
var $boards = $("<select>")
.attr("id", "boards")
.text("Loading Boards...")
.appendTo("#output");
Trello.get("/boards/BOARD_ID/lists", function(boards) {
$boards.empty();
$.each(boards, function(ix, board) {
$("<option>")
.attr({href: board.url, target: "trello", value : board.id, name : board.id, id : board.id})
.addClass("board")
.text(board.name)
.appendTo($boards);
});
});
var $cards = $("<div>")
.text("Loading Cards...")
.appendTo("#outputCards")
.appendTo("#demo");
// This is where I'm trying to return the value
document.getElementById("demo").innerHTML = $(".board").val();
var resource = "lists/LIST_ID/cards";
Trello.get(resource, function(cards) {
$cards.empty();
$.each(cards, function(ix, card) {
$("<a>")
.attr({href: card.url, target: "trello"})
.addClass("card")
.text(card.name)
.appendTo($cards);
});
});
HTML 输出如下:
<label>Choose from a List of Boards</label>
<div id="output">
<select id="boards">
<option target="trello" value="LIST_ID" name="LIST_ID" id="LIST_ID" class="board">
List One
</option>
...
</select>
</div>
<label>Display Cards Below for Board Selected</label>
<div id="outputCards"></div>
<p id="demo">undefined</p>
我认为这里的主要问题是 board
class 仅被添加到 Trello.get
回调中的元素。
由于此代码是异步执行的,因此您很可能在执行回调中的代码之前 $(".board").val()
,这意味着 `$(".board") 未返回任何元素。
我会考虑这样的事情
Trello.get("/boards/BOARD_ID/lists", function(boards) {
$boards.empty();
$.each(boards, function(ix, board) {
$("<option>")
.attr({href: board.url, target: "trello", value : board.id, name : board.id, id : board.id})
.addClass("board")
.text(board.name)
.appendTo($boards);
});
// This is where I'm trying to return the value
$('#board').change(function () {
document.getElementById("demo").innerHTML = $(".board:selected").val();
});
});