在 PowerShell 中过滤以（一个或两个）斜杠开头的字符串

Question

我试图找出以一个斜杠 (/) 和两个斜杠 (//) 开头的字符串。例如，以下是包含几个字符串的数组：以下是我正在尝试的代码：

$array = @("/website","//windows_service","/console_app","//windows","///IIS","test")
$arraysplit = $array.split(',');
Foreach ($string in $arraysplit)
{
    if ($string.StartsWith("/"))
    {
        Write-Host "$string has one slash."
    }
    elseif($string.StartsWith("//"))
    {
        Write-Host "$string has two slashes."
    }
    else
    {
        #I want to exit only when below conditions meet
        #1. if string doesnot have any slash or
        #2. if string has more than two slashes
        Write-Host "$string has more number of slashes or it doesnot have any slash. Exiting"
        Exit -1
    }
}

我不想写更多的 if 条件来过滤这些东西，但这没有按预期工作。我想我应该改变逻辑来达到要求。有人可以给我建议吗（我正在寻找动态方法）

Answer 1

我会使用正则表达式编写一个 if 测试来匹配任何不是以一个或两个斜杠开头的行。尝试：

$array = @("/website","//windows_service","/console_app","//windows","///IIS","test")
Foreach ($string in $array)
{
    if ($string -notmatch '^\/{1,2}[^\/]')
    {
        Write-Host "$string has more number of slashes or it doesnot have any slash. Exiting"
        Exit -1
    }
}

Answer 2

只需反转你的测试，因为如果一个单词以 // 开头，它以 /

开头

$array = @("/website","//windows_service","/console_app","//windows","///IIS","test")
$arraysplit = $array.split(',');
Foreach ($string in $arraysplit)
{
    if ($string.StartsWith("//"))
    {
        Write-Host "$string has two slash."
    }
    elseif($string.StartsWith("/"))
    {
        Write-Host "$string has one slashes."
    }
    else
    {
        #I want to exit only when below conditions meet
        #1. if string doesnot have any slash or
        #2. if string has more than two slashes
        Write-Host "$string has more number of slashes or it doesnot have any slash. Exiting"
        Exit -1
    }
}

Answer 3

if ($string -match '^/*') { write-host $matches[0].length slashes }

是@wOxxOm 发布的答案。谢谢

在 PowerShell 中过滤以（一个或两个）斜杠开头的字符串

Filter the strings which startswith (one or two) slashes in PowerShell

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powershell-2.0