将字符串分成 java 中的句子（在指定组的符号出现后）

Question

所以我写了下面的代码：

String text = "This is a string.        I want to break it into sentences";
String[] sentences = text.split("\."); 

for (int i = 0; i < sentences.length; i++)
    System.out.println(sentences[i]);

这段代码的输出是：

This is a string
        I want to break it into sentences

如何更改此代码以便

每个新句子不仅会在“.”之后创建，还会在“！”之后创建。或“？”。
句首不会有空格。

例如，如果我们有以下字符串

String text = "This is a string!   Is this a string?         I want to break it into sentences";

那么输出应该是：

This is a string
Is this a string
I want to break it into sentences

Answer 1

您可以使用字符 class 围绕点 (.)、? 或 ! 字符之一进行拆分。要删除句子开头（也可能是结尾）的 space，您可以简单地 trim 结果字符串：

String[] sentences = text.split("[.!?]");

for (int i = 0; i < sentences.length; i++) {
    System.out.println(sentences[i].trim());
}

Answer 2

将定界符放在字符 class 内，并在字符 class 旁边添加 \s* ，这样它也将占用以下零个或多个空格。

String[] sentences = text.split("[?!.]\s*");

示例：

String text = "This is a string!   Is this a string?         I want to break it into sentences";
String[] parts = text.split("[?!.]\s*"); 
for(String i: parts)
{
System.out.println(i);
}

输出：

This is a string
Is this a string
I want to break it into sentences

将字符串分成 java 中的句子（在指定组的符号出现后）

Breaking string into sentences in java (after symbol of specified group occurs)

java

regex

eclipse

string

text