在额外的 WebView class 中而不是在内部 class 中开始意图?

Starting intent in an extra WebView class instead in an inner class?

我想让我的 MainActivity 小而清晰。所以我为 WebView 创建了 一个单独的 class 而不是内部 class 这样:

protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    mWebView = (WebView) findViewById(R.id.activity_main_webview);
    WebSettings webSettings = mWebView.getSettings();
    webSettings.setJavaScriptEnabled(true);
    mWebView.addJavascriptInterface(new JavaScriptInterface(this), "Android");
    mWebView.setWebViewClient(new CustomWebViewClient()); 

但现在我想用 openInAppBrowser 方法在 CustomWebViewClient 中开始一个新的 activity:

public class CustomWebViewClient extends WebViewClient {

    @Override
    public boolean shouldOverrideUrlLoading(WebView view, String url) {
        if(Uri.parse(url).getHost().endsWith(PROJECT_REMOTE)) {
            return false;
        } else {
            openInAppBrowser(this, url);
        }
        return true;
    }
    private void openInAppBrowser(Activity activity, String url) {
        Intent intent = new Intent(activity, InAppBrowser.class);
        intent.putExtra("url", url);
        activity.startActivity(intent);
    }

由于 thisMainActivity.this 在这里不起作用,我如何才能引用 MainActivity 来使该方法起作用?或者 MainActivity 内部的 class 是更好的还是唯一的选择?

protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    mWebView = (WebView) findViewById(R.id.activity_main_webview);
    WebSettings webSettings = mWebView.getSettings();
    webSettings.setJavaScriptEnabled(true);
    mWebView.addJavascriptInterface(new JavaScriptInterface(this), "Android");
    mWebView.setWebViewClient(new CustomWebViewClient(this)); 



public class CustomWebViewClient extends WebViewClient {

Activity activity;

public CustomWebViewClient (Activity activity) {
    this.activity= activity;

}

    @Override
    public boolean shouldOverrideUrlLoading(WebView view, String url) {
        if(Uri.parse(url).getHost().endsWith(PROJECT_REMOTE)) {
            return false;
        } else {
            openInAppBrowser(url);
        }
        return true;
    }
    private void openInAppBrowser(String url) {
        Intent intent = new Intent(activity, InAppBrowser.class);
        intent.putExtra("url", url);
        activity.startActivity(intent);
    }

根据要求。我不确定这是否有效,这就是为什么我没有首先回答的原因。