搜索分页

Question

我的问题是基于这个写得很好的教程： http://www.sanwebe.com/2013/03/loading-more-results-from-database

演示： http://www.sanwebe.com/downloads/43-load-more-results

本质上我是想实现这个+搜索。从某种意义上说，结果将根据用户的搜索查询进行填充。

让我用代码详细说明：

这是主页

<?php
include("includes/db.php");




$results = mysqli_query($con,"SELECT COUNT(*) FROM courses");
$get_total_rows = mysqli_fetch_array($results); //total records

//break total records into pages
$item_per_page = 10;
$total_pages = ceil($get_total_rows[0]/$item_per_page); 

?>
<html>
<head>

    <script type="text/javascript" src="js/jquery-1.9.0.min.js"></script>

<script>
$(document).ready(function() {

    var track_click = 0; //track user click on "load more" button, righ now it is 0 click

    var total_pages = <?php echo $total_pages; ?>;

    $('#results').load("fetch_pages.php", {'page':track_click}, function() {track_click++;}); //initial data to load


    $(".load_more").click(function (e) { //user clicks on button

        $(this).hide(); //hide load more button on click
        $('.animation_image').show(); //show loading image

        if(track_click <= total_pages) //user click number is still less than total pages
        {
            //post page number and load returned data into result element
            $.post('fetch_pages.php',{'page': track_click}, function(data) {

                $(".load_more").show(); //bring back load more button

                $("#results").append(data); //append data received from server

                //scroll page smoothly to button id
                $("html, body").animate({scrollTop: $("#load_more_button").offset().top}, 500);

                //hide loading image
                $('.animation_image').hide(); //hide loading image once data is received

                track_click++; //user click increment on load button

            }).fail(function(xhr, ajaxOptions, thrownError) { //any errors?
                alert(thrownError); //alert with HTTP error
                $(".load_more").show(); //bring back load more button
                $('.animation_image').hide(); //hide loading image once data is received
            });


            if(track_click >= total_pages-1) //compare user click with page number
            {
                //reached end of the page yet? disable load button
                $(".load_more").attr("disabled", "disabled");
            }
         }

        });
});
</script>
</head>
<body>
    <center>
    <form method="get" action="testSearch.php" enctype="multipart/form-data" autocomplete="off">
<input type="text" class="search" id="searchid" name="user_query" id="searchBar" placeholder="Search for courses" />
          <input type="submit" id="searchButton"  name="search" value="search" class="btn btn-danger" autocomplete="off"/>
<div id="results"></div>
<div align="center">
<button class="load_more" id="load_more_button">load More</button>
<div class="animation_image" style="display:none;"><img src="ajax-loader.gif"> Loading...</div>
</div>

</body>
</html>

这是 fetch_page.php，基本上是从以下位置填充内容的地方：

<?php
include("includes/db.php"); 

//sanitize post value
$page_number = filter_var($_POST["page"], FILTER_SANITIZE_NUMBER_INT, FILTER_FLAG_STRIP_HIGH);

//throw HTTP error if page number is not valid
if(!is_numeric($page_number)){
  header('HTTP/1.1 500 Invalid page number!');
  exit();
}
$item_per_page = 10;
//get current starting point of records
$position = ($page_number * $item_per_page);

//Limit our results within a specified range. 
$results = mysqli_query($con,"SELECT course_title, course_date1, course_provider,course_sdesc FROM courses ORDER BY course_date1 DESC LIMIT $position, $item_per_page");

//output results from database
echo '<ul class="page_result">';
while($row = mysqli_fetch_array($results))
{
  echo '<li id="item_'.$row["course_title"].'"><span class="page_name">'.$row["course_date1"].') '.$row["course_provider"].'</span><span class="page_message">'.$row["course_sdesc"].'</span></li>';
}
echo '</ul>';
?>

现在深入了解细节：

下面是允许搜索的表格（在索引页的内容中）：

<form method="get" action="testSearch.php" enctype="multipart/form-data" autocomplete="off">
    <input type="text" class="search" id="searchid" name="user_query" id="searchBar" placeholder="Search for courses" />

我正在考虑做的事情，但我并没有那么成功，如下所示：在主页的标题中（在计算分页的页面代码中）：我正在考虑进行以下更改：

 if(isset($_GET['user_query']))
    {

 $search_query = $_GET['user_query'];
$results = mysqli_query($con,"SELECT COUNT(*) FROM courses where course_title like '%$search_query%'");
$get_total_rows = mysqli_fetch_array($results); //total records

//break total records into pages
$item_per_page = 10;
$total_pages = ceil($get_total_rows[0]/$item_per_page); 
}
?>

如果尝试通过将代码调整为以下内容来在获取页面中执行相同的操作：

  <?php
include("includes/db.php"); 

  if(isset($_GET['user_query']))
    {

       $search_query = $_GET['user_query'];

//sanitize post value
$page_number = filter_var($_POST["page"], FILTER_SANITIZE_NUMBER_INT, FILTER_FLAG_STRIP_HIGH);

//throw HTTP error if page number is not valid
if(!is_numeric($page_number)){
  header('HTTP/1.1 500 Invalid page number!');
  exit();
}
$item_per_page = 10;
//get current starting point of records
$position = ($page_number * $item_per_page);

//Limit our results within a specified range. 
$results = mysqli_query($con,"SELECT course_title, course_date1, course_provider,course_sdesc FROM courses ORDER BY course_date1 where course_title like '%$search_query%' DESC LIMIT $position, $item_per_page");

//output results from database
echo '<ul class="page_result">';
while($row = mysqli_fetch_array($results))
{
  echo '<li id="item_'.$row["course_title"].'"><span class="page_name">'.$row["course_date1"].') '.$row["course_provider"].'</span><span class="page_message">'.$row["course_sdesc"].'</span></li>';
}
echo '</ul>';
}
?>

然后什么也没有发生。

我认为问题在于我试图从另一个页面的 url 中检索变量。换句话说，fetch_page.php 试图从 testSearch.php 中检索 user_query=，我不确定如何解决它。

新方法： 我把它放在现场，所以你可以知道我想做什么： http://testapplication220-env.elasticbeanstalk.com/testSearch.php

在 testSearch.php（主页面上，我这样做是为了获取用户搜索查询并稍后检索）。

session_start();

 $search_query = $_GET['user_query'];
 $_SESSION['userSearch'] = $search_query;
$results = mysqli_query($con,"SELECT COUNT(*) FROM courses where course_title like '%$search_query%'");

然后获取页面（功能，我尝试执行以下操作）：

session_start();
//sanitize post value
$page_number = filter_var($_POST["page"], FILTER_SANITIZE_NUMBER_INT, FILTER_FLAG_STRIP_HIGH);

//throw HTTP error if page number is not valid
if(!is_numeric($page_number)){
  header('HTTP/1.1 500 Invalid page number!');
  exit();
}
$item_per_page = 10;
//get current starting point of records
$position = ($page_number * $item_per_page);

//Limit our results within a specified range. 
$results = mysqli_query($con,"SELECT course_title, course_date1, course_provider,course_sdesc FROM courses ORDER BY course_date1 where course_title like '%$_SESSION['userSearch']%' DESC LIMIT $position, $item_per_page");

Answer 1

我想我找到了答案

如果页面变量不包含数字，您将抛出 500 错误。

并且您使用 filter_var 函数

从 post 数组转义页面变量

但根据 php.net filter_var 只会验证数据，不会将其转换为否。我已经在 phpfiddle 中测试过它 returns string.

var_dump(filter_var('23',FILTER_SANITIZE_NUMBER_INT, FILTER_FLAG_STRIP_HIGH));

所以在通过 is_numeric 比较页面之前，您必须将其转换为整数，这可以通过以下方式完成

$page = (int) $page;

搜索分页

Pagination with Search

javascript

php

mysql

ajax

mysqli