Symfony3 在类型文件中创建没有实体的表单

Question

我在我的控制器中创建了一个表单，如下所示：

$data = array ();
$formBuilder = $this->createFormBuilder ( $data );
$formBuilder->add( 'Field1', NumberType::class, array(
                    'constraints' => array(
                            new NotBlank(),
                    ),
            ) )
            ->add ( 'Field2', NumberType::class, array(
                    'constraints' => array(
                            new NotBlank(),
                    )
...);
$form = $formBuilder->getForm ();

我正在尝试将我创建的表单放入类型文件中。我是这样做的，但是没有创建表单，我无法在 view.I 中显示表单字段，不明白为什么。

#in ControlController
$data = array ();
$formBuilder= $this->createFormBuilder(ControlType::class, $data);
$form = $formBuilder->getForm ();

#in ControlType
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder->add( 'Field1', NumberType::class, array(
                    'constraints' => array(
                            new NotBlank(),
                    ),
            ) )
            ->add ( 'Field2', NumberType::class, array(
                    'constraints' => array(
                            new NotBlank(),
                    )....;
}

编辑 1：我已经尝试了你告诉我的所有事情，但它仍然不起作用。我的代码现在看起来像这样：

#in ControlController
$data = ['Field1' => null, 'Field2' => null];
$formBuilder= $this->createFormBuilder(ControlType::class, $data);
$form = $formBuilder->getForm ();
return $this->render ( 'MeTestBundle:Control:index.html.twig', array (
            'form' => $form->createView () 
    ) );

#in ControlType
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder->add( 'Field1', NumberType::class, array(
                            'mapped' => false,
    ) )
    ->add ( 'Field2', NumberType::class, array(
            'constraints' => array(
                    new NotBlank(),
            ),
            'mapped' => false
    ))
    ->add ( 'save', SubmitType::class, array (
            'label' => 'Control'
    ));
}

public function configureOptions(OptionsResolver $resolver)
{
    $resolver->setDefaults(array(
            'data_class' => Control::class,
    ));
}

但现在我的错误是：

The options "Field1", "Field2" do not exist. Defined options are: "action", 
"allow_extra_fields", "attr", "auto_initialize", "block_name", "by_reference", 
"compound", "constraints", "csrf_field_name", "csrf_message", "csrf_protection", 
"csrf_token_id", "csrf_token_manager", "data", "data_class", "disabled", 
"empty_data", "error_bubbling", "error_mapping", "extra_fields_message", 
"inherit_data", "invalid_message", "invalid_message_parameters", "label", 
"label_attr", "label_format", "mapped", "method", "post_max_size_message", 
"property_path", "required", "translation_domain", "trim", 
"upload_max_size_message", "validation_groups".

Answer 1

您创建表单的控制器代码似乎有误。

Controller 中 createFormBuilder 的签名定义如下：

public function createFormBuilder($data = null, array $options = array())

你想要的应该是：

$data = ['Field1' => null, 'Field2' => null];
$form = $this->createForm(ControlType::class, $data);
return $this->render ( 'MeTestBundle:Control:index.html.twig', array (
        'form' => $form->createView () 
));

编辑：另外，如果您不打算使用数据对象，则不应设置 data_class。在这种情况下，只需将 configureOptions 留空即可。如果你想使用实体，你应该将它的实例作为 $data 而不是简单的数组传递。

Symfony3 在类型文件中创建没有实体的表单

Symfony3 create form without entity in type file

php

symfony-forms

symfony