如何拆分字符串并将其存储在临时变量中

Question

我有一个数据，它只是一个字符串b'365,7,7675962680, 4040。我想拆分这个数据，只想存储7675962680 到任何临时 variable.I 不知道，如何拆分和挑选 python 中的特定数据。我有一个小代码，请帮我解决这些问题

manage.py

def data(self, data):
    data1 = data # b'365,7,7675962680, 4040
    # want to split these and store 7675962680 in a variable

Answer 1

你可以使用这样的东西：

def get_data(data):
    data = data.decode()
    data_list = data.split(',')
    return data_list[2]

a = get_data(b'365,7,7675962680, 4040')
print(a)
>> 7675962680

Answer 2

假设，

s ="365,7,7675962680, 4040"
s.split(',')[2]
'7675962680'

Answer 3

def data(self, data):
    # data = b'365,7,7675962680, 4040
    # data MUST be converted to str before splitting it
    data1 = data.decode('utf8').split(',')[2]
    print(data1)  # 7675962680
    print(type(data1))  # str

如何拆分字符串并将其存储在临时变量中

how can I split a string and store it in a temporary variable

python

django

tornado

python-2.7

python-3.x