如何获取 mySql 中用户未申请的所有职位

Question

我必须 tables、job_postings 和 job_applies。我怎样才能获得该用户尚未申请的所有工作？

以下是我的 job_postings table:

的专栏

id, user_id, title, description, duties, salary, child_count, benefits, created_at, updated_at

下面是 job_applies table

的列

user_id, posting_id, status, created_at, updated_at

我尝试了什么：

  $job_postings =  DB::table('job_postings')
        ->select(
          'job_postings.title',
          'job_postings.description',
          'job_postings.duties',
          'job_postings.salary',
          'job_postings.child_count',
          'job_postings.benefits',
          'job_postings.created_at',
          'job_postings.id AS posting_id',
          'job_postings.user_id')
        ->join('job_applies', 'job_applies.posting_id', '!=', 'job_postings.id')
        ->where('job_applies.user_id', "=" , user()->id)
        ->get();

Answer 1

在 Mysql 你应该写（用你的字段列表替换 *）。你可以适应你的语言

 SELECT * 
 FROM JOB_POSTING A
 LEFT JOIN JOB_APPLIES B ON B.POSTING_ID = A.ID AND B.USER_ID = A.USER_ID
 WHERE B.POSTING_ID IS NULL

或

 SELECT * 
 FROM JOB_POSTING A
 WHERE NOT EXISTS (SELECT 1 FROM JOB_APPLIES B WHERE B.POSTING_ID = A.ID  AND B.USER_ID = A.USER_ID)

如何获取 mySql 中用户未申请的所有职位

How to get all jobs that user has not applied to in mySql

mysql