SQL 查询查找特定部件维修后的最多 3 个交易

Question

我的数据与这个非常庞大的示例类似，因此理想情况下需要高效的代码。我想在充电器维修后找到那些交易（最多 3 个）。

TRANSACTION_ID  REPAIR_DATE CUSTOMER_ID    COMPONENT   LABOR_CODE_DESC ....
28289           6/25/2015   AH123        LAPTOP       CHARGER REPAIR
28235           6/29/2015    AH123       LAPTOP         CHIP REPLACE
258978         6/27/2013      HW687      PHONE      TOUCH SCREEN
28223           6/2/2014     AH123       LAPTOP      BATTERY REPAIR
215678          9/7/2014       HW687      PHONE         SIM REPAIR
527808          7/30/2016      HW687      LAPTOP         BATTERY REPAIR
567976          7/28/2014      HW687      LAPTOP         CHARGER REPAIR
7678698         8/68/2015     AH123        LAPTOP        BATTERY REPAIR
9987908          5/7/2006       TU890       PHONE         SIM REPAIR
.....


OUTPUT
TRANSACTION_ID  REPAIR_DATE CUSTOMER_ID COMPONENT    LABOR_CODE_DESC ....
28235           6/29/2015    AH123       LAPTOP         CHIP REPLACE
7678698         8/68/2015      AH123        LAPTOP        BATTERY REPAIR
527808          7/30/2016     HW687      LAPTOP          BATTERY REPAIR
215678          9/7/2014       HW687      PHONE     SIM REPAIR

.....

所以我想要的是那些进行过充电器维修且在充电器维修日期之后最多有 3 次交易的客户 ID 交易

SELECT TRANSACTION_ID, REPAIR_DATE,CUSTOMER_ID,LABOR_CODE_DESC from table 
where customer_id IN (SELECT CUSTOMER_ID from table where LABOR_CODE_DESC 
like '%CHARGER REPAIR%')

不确定如何在充电器维修后扩展到最多 3 个交易

Answer 1

您可以通过以下方式获得所有此类交易：

select t.*
from table t
where t.repair_date > (select t2.repair_date
                       from table t2
                       where t2.customer_id = t.customer_id and
                             labor_code_desc like '%CHARGER REPAIR%'
                      );

将此限制为每个客户 3 个有点诡计，但您可以使用 window 函数：

select t.*
from (select t.*,
             row_number() over (partition by customer_id order by repair_date) as seqnum
      from (select t.*,
                   max(case when labor_code_desc like '%CHARGER REPAIR%' then repair_date end) over (partition by customer_id) as max_crd
            from table t
           ) t
      where t.repair_date > max_crd
     ) t
where seqnum <= 3;

Answer 2

此returns充电器维修日期后三排：

SELECT *
FROM tab
QUALIFY 
   -- check if any of the three previous rows contains 'CHARGER REPAIR'
   Max(CASE WHEN LABOR_CODE_DESC = 'CHARGER REPAIR' THEN 1 ELSE 0 END)
   Over (PARTITION BY CUSTOMER_ID
         ORDER BY REPAIR_DATE
         ROWS BETWEEN 3 Preceding AND 1 Preceding) = 1

编辑：

仅获取修复日期在未来 10 天内的行：

   -- check if any of the previous rows contains 'CHARGER REPAIR'
   -- and the current REPAIR_DATE is within 10 days after that repair
   Max(CASE WHEN LABOR_CODE_DESC = 'CHARGER REPAIR' THEN REPAIR_DATE END)
   Over (PARTITION BY CUSTOMER_ID
         ORDER BY REPAIR_DATE
         ROWS BETWEEN Unbounded Preceding AND 1 Preceding) >= REPAIR_DATE - 10

SQL 查询查找特定部件维修后的最多 3 个交易

SQL query to find maximum of 3 transactions after the specific part repair

sql

teradata