Laravel 验证 required_without_all
Laravel validation required_without_all
说我笨,但我听不懂 :)
我想设置验证器规则,因此仅当存在两个字段之一(广告组或 all_adgroups)时它才会通过。
这是我的控制器:
$this->validate($request,
[
'new_target_cpa_value' => 'required|numeric',
'adgroups' => 'exists:google.ad_groups,id|required_without_all:all_agroups',
'all_agroups' => 'required_without_all:adgroups'
]
);
dd($request->all());
这里是 dd:
"_token" => "aHjluUXPuZpEbglmVt4UePhriGvRWDOjk3OgfF88"
"new_target_cpa_value" => "123"
"adgroups" => array:1 [▶]
"all_agroups" => "1"
试试这个:
$this->validate($request,
[
'new_target_cpa_value' => 'required|numeric',
'adgroups' => 'exists:google.ad_groups,id',
'all_agroups' => 'required_unless:adgroups,null'
]
);
说我笨,但我听不懂 :) 我想设置验证器规则,因此仅当存在两个字段之一(广告组或 all_adgroups)时它才会通过。
这是我的控制器:
$this->validate($request,
[
'new_target_cpa_value' => 'required|numeric',
'adgroups' => 'exists:google.ad_groups,id|required_without_all:all_agroups',
'all_agroups' => 'required_without_all:adgroups'
]
);
dd($request->all());
这里是 dd:
"_token" => "aHjluUXPuZpEbglmVt4UePhriGvRWDOjk3OgfF88"
"new_target_cpa_value" => "123"
"adgroups" => array:1 [▶]
"all_agroups" => "1"
试试这个:
$this->validate($request,
[
'new_target_cpa_value' => 'required|numeric',
'adgroups' => 'exists:google.ad_groups,id',
'all_agroups' => 'required_unless:adgroups,null'
]
);