使块从 pygame 中的一条线上反弹

Question

运行下面的代码允许 3 个方块在屏幕上移动，然后假设它们自由漫游，从边缘弹起，直到它们遇到一条蓝线。他们也被严格命令从那条线上反弹。当块来自右侧并从线的右侧反弹，但不是来自左侧并从线的左侧反弹时，我能够做到这一点。请查看代码了解更多信息。

import pygame, sys, time
from pygame.locals import *

pygame.init()
WINDOWWIDTH = 200
WINDOWHEIGHT = 300
screen = pygame.display.set_mode((WINDOWWIDTH, WINDOWHEIGHT), 0, 32)
pygame.display.set_caption('Animation')

DOWNLEFT = 1
DOWNRIGHT = 3
UPLEFT = 7
UPRIGHT = 9

MOVESPEED = 1

BLACK = (0, 0, 0)
RED = (255, 0, 0)
GREEN = (0, 255, 0)
BLUE = (0, 0, 255)


b1 = {'rect':pygame.Rect(0, 50, 25, 25), 'color':RED, 'dir':DOWNRIGHT}
b2 = {'rect':pygame.Rect(0, 100, 25, 25), 'color':GREEN, 'dir':DOWNRIGHT}
b3 = {'rect':pygame.Rect(0, 150, 25, 25), 'color':BLUE, 'dir':DOWNRIGHT}
blocks = [b1, b2, b3]

while True:
    # check for the closing of the 'x' button
    for event in pygame.event.get():
        if event.type == QUIT:
            pygame.quit()
            sys.exit()
    screen.fill(BLACK)
    pygame.draw.line(screen,BLUE,(150,0),(150,150),5)


    for b in blocks:
        #moves the blocks
        if b['dir'] == DOWNLEFT:
            b['rect'].left -= MOVESPEED
            b['rect'].top += MOVESPEED
        if b['dir'] == DOWNRIGHT:
            b['rect'].left += MOVESPEED
            b['rect'].top += MOVESPEED
        if b['dir'] == UPLEFT:
            b['rect'].left -= MOVESPEED
            b['rect'].top -= MOVESPEED
        if b['dir'] == UPRIGHT:
            b['rect'].left += MOVESPEED
            b['rect'].top -= MOVESPEED

        # check if the block has move out of the window
        if b['rect'].top < 0:
            # block has moved past the top
            if b['dir'] == UPLEFT:
                b['dir'] = DOWNLEFT
            if b['dir'] == UPRIGHT:
                b['dir'] = DOWNRIGHT
        if b['rect'].bottom > WINDOWHEIGHT:
            # block has moved past the bottom
            if b['dir'] == DOWNLEFT:
                b['dir'] = UPLEFT
            if b['dir'] == DOWNRIGHT:
                b['dir'] = UPRIGHT
        if b['rect'].left < 0:
            # block has moved past the left side
            if b['dir'] == DOWNLEFT:
                b['dir'] = DOWNRIGHT
            if b['dir'] == UPLEFT:
                b['dir'] = UPRIGHT
        if b['rect'].right > WINDOWWIDTH:
            # block has moved past the right side
            if b['dir'] == DOWNRIGHT:
                b['dir'] = DOWNLEFT
            if b['dir'] == UPRIGHT:
                b['dir'] = UPLEFT
        if b['rect'].left < 150 and b['rect'].top > 0 and b['rect'].top < 150:
            if b['dir'] == DOWNLEFT:
                b['dir'] = DOWNRIGHT
            if b['dir'] == UPLEFT:
                b['dir'] = UPRIGHT
##        if b['rect'].right > 150 and b['rect'].top > 0 and b['rect'].top < 150:
##            if b['dir'] == DOWNLEFT:
##                b['dir'] = DOWNRIGHT
##            if b['dir'] == UPLEFT:
##                b['dir'] = UPRIGHT
        print(b['rect'].right)
        pygame.draw.rect(screen, b['color'], b['rect'])

    pygame.display.update()
    time.sleep(0.0001)

Answer 1

import pygame, sys, time
from pygame.locals import *

pygame.init()
WINDOWWIDTH = 200
WINDOWHEIGHT = 300
screen = pygame.display.set_mode((WINDOWWIDTH, WINDOWHEIGHT), 0, 32)
pygame.display.set_caption('Animation')

DOWNLEFT = 1
DOWNRIGHT = 3
UPLEFT = 7
UPRIGHT = 9

MOVESPEED = 1

BLACK = (0, 0, 0)
RED = (255, 0, 0)
GREEN = (0, 255, 0)
BLUE = (0, 0, 255)


b1 = {'rect':pygame.Rect(0, 50, 25, 25), 'color':RED, 'dir':DOWNRIGHT}
b2 = {'rect':pygame.Rect(0, 100, 25, 25), 'color':GREEN, 'dir':DOWNRIGHT}
b3 = {'rect':pygame.Rect(0, 150, 25, 25), 'color':BLUE, 'dir':DOWNRIGHT}
blocks = [b1, b2, b3]


while True:
# check for the closing of the 'x' button
    for event in pygame.event.get():
        if event.type == QUIT:
            pygame.quit()
            sys.exit()
    screen.fill(BLACK)
    pygame.draw.line(screen,BLUE,(150,0),(150,150),5)


    for b in blocks:
    #moves the blocks
        if b['dir'] == DOWNLEFT:
            b['rect'].left -= MOVESPEED
            b['rect'].top += MOVESPEED
        if b['dir'] == DOWNRIGHT:
            b['rect'].left += MOVESPEED
            b['rect'].top += MOVESPEED
        if b['dir'] == UPLEFT:
            b['rect'].left -= MOVESPEED
            b['rect'].top -= MOVESPEED
        if b['dir'] == UPRIGHT:
            b['rect'].left += MOVESPEED
            b['rect'].top -= MOVESPEED

    # check if the block has move out of the window
        if b['rect'].top < 0:
        # block has moved past the top
            if b['dir'] == UPLEFT:
                b['dir'] = DOWNLEFT
            if b['dir'] == UPRIGHT:
                b['dir'] = DOWNRIGHT
        if b['rect'].bottom > WINDOWHEIGHT:
        # block has moved past the bottom
            if b['dir'] == DOWNLEFT:
                b['dir'] = UPLEFT
            if b['dir'] == DOWNRIGHT:
                b['dir'] = UPRIGHT
        if b['rect'].left < 0:
        # block has moved past the left side
            if b['dir'] == DOWNLEFT:
                b['dir'] = DOWNRIGHT
            if b['dir'] == UPLEFT:
                b['dir'] = UPRIGHT
        if b['rect'].right > WINDOWWIDTH:
        # block has moved past the right side
            if b['dir'] == DOWNRIGHT:
                b['dir'] = DOWNLEFT
            if b['dir'] == UPRIGHT:
                b['dir'] = UPLEFT
        if b['dir'] == UPLEFT or b['dir'] == DOWNLEFT: # In this case it's rather easy to check for the exact conditions when direction changes should be made. Being the movement speed is only 1, at some point the b['rect'].right/left will be exactly 150. It's easier to check for that than deal with greater than less than problems which tend to only work for one way. If movement was higher than one you'd have to switch to short ranges instead.
            if b['rect'].left == 150 and b['rect'].top > 0 and b['rect'].top < 150:
                if b['dir'] == DOWNLEFT:
                    b['dir'] = DOWNRIGHT
                if b['dir'] == UPLEFT:
                    b['dir'] = UPRIGHT

        if b['dir'] == DOWNRIGHT or b['dir'] == UPRIGHT:
            if b['rect'].right == 150 and b['rect'].top < 150:
                if b['dir'] == DOWNRIGHT:
                    b['dir'] = DOWNLEFT
                if b['dir'] == UPRIGHT:
                    b['dir'] = UPLEFT
        print(b['rect'].right)
        pygame.draw.rect(screen, b['color'], b['rect'])

    pygame.display.update()
    time.sleep(0.00001)

这个更正后的代码更符合我的想法。

使块从 pygame 中的一条线上反弹

Making a block bounce off a line in pygame

python

pygame

python-3.4