通过 JS 自动提交表单(Timeout,TimeInterval)

Autosubmit form via JS (Timeout, TimeInterval)

我想创建简单的自动提交。例如,如果用户 1 秒未在输入中键入任何内容或按回车键,则提交。我的代码:

$(document).on('keypress', $('input'), function(e) {
  console.log('clear')
  
  clearInterval(SubmitInterval);
  
  if (e.which == 13) {
    console.log('submit')
  }
  
  var SubmitInterval = setInterval(function() {
    console.log('submit')
    clearInterval(SubmitInterval);
  }, 1000);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type=text id=1 />

但效果不佳。 谢谢

问题是由于您在每次按键时重新定义了 SubmitInterval 变量。而是在事件处理程序之外声明一次。试试这个:

var submitInterval;

$(document).on('keypress', 'input', function(e) {
  console.log('clear')
  
  clearInterval(submitInterval);
  
  if (e.which == 13) {
    console.log('submit')
  }
  
  submitInterval = setInterval(function() {
    console.log('submit')
    clearInterval(submitInterval);
  }, 1000);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type=text id=1 />

现在一切正常。谢谢

var SubmitInterval;
$(document).on('keypress', $('input'), function(e) {
  clearInterval(SubmitInterval);
  SubmitInterval = setInterval(function () {
    console.log('submit');
    clearInterval(SubmitInterval);
  },1700);
  if(e.which == 13) {
   console.log('submit');
   clearInterval(SubmitInterval);
 };
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type=text />