如何 "hold" 随机生成颜色？

Question

random_turtle_color 借自 this page.

import turtle, random
r = lambda: random.randint(0,255)
print('#%02X%02X%02X' % (r(),r(),r()))

turtle.width(10) #What does this line do?
length = 5
for count in range(100):
    colors = (z) #I want the randomly generated hexadecimal color to be #the pen in the drawing
    turtle.speed(0)
    turtle.forward(length)
    turtle.right(135)
    length = length + 5

Answer 1

使用 ''.format() 而不是 print()。如果您想每次都获得不同的颜色，请将 z 分配行移动到 for 循环中：

import turtle, random
r = lambda: random.randint(0,255)
z = '#{:02X}{:02X}{:02X}'.format(r(),r(),r())

turtle.width(10) #What does this line do?
length = 5
for count in range(100):
    colors = (z) #I want the randomly generated hexadecimal color to be #the pen in the drawing
    turtle.speed(0)
    turtle.forward(length)
    turtle.right(135)
    length = length + 5

Answer 2

您缺少的一个关键部分是告诉乌龟使用您通过 turtle.pencolor() 生成的颜色。这是一个修改后的例子：

import turtle
import random

color_values = [random.randrange(0, 256) for _ in 'rgb']
hex_string = '#{:02X}{:02X}{:02X}'.format(*color_values)

turtle.speed('fastest')
turtle.pencolor(hex_string)  # Set the pen color

turtle.width(10)  # Width in pixels of the lines drawn (constant)

length = 5  # Length in pixels of the lines drawn (grows)

for _ in range(100):
    turtle.forward(length)
    turtle.right(135)
    length += 5

turtle.hideturtle()
turtle.done()

您不需要使用十六进制字符串来设置颜色，如果匹配颜色模式，您可以直接传递颜色值。这是一个返工，它在循环过程中也改变了颜色：

import turtle
import random

turtle.colormode(255)
turtle.speed('fastest')

turtle.width(10)  # Width in pixels of the lines drawn (constant)

length = 5  # Length in pixels of the lines drawn (grows)

for _ in range(100):
    color_values = [random.randrange(0, 256) for _ in 'rgb']
    turtle.pencolor(color_values)  # Set the pen color

    turtle.forward(length)
    turtle.right(135)
    length += 5

turtle.hideturtle()
turtle.done()

输出

Answer 3

有关某些解释，请参阅下面代码中的注释：

import turtle, random
r = lambda: random.randint(0,255)
z = '#{:02X}{:02X}{:02X}'.format(r(),r(),r())
print(z)
length = 5
turtle.pen(fillcolor=z,pencolor=z,pensize=1) # pensize= width of drawed line (here 1 pixel) 
turtle.begin_fill() # Called just before drawing a shape which is to be filled.
for _ in range(100): # without '_' unused numbers are generated
    turtle.speed(0)
    turtle.forward(length)
    turtle.right(135)
    length = length + 5
turtle.end_fill() # It's question of taste, but I like the filled figure better ...
turtle.done()     # the turtle window will stay open

给出：

Answer 4

你的问题让我想到了 faker, a nice package to generate random data, including random colors，即：

import random
from faker import Faker
length = 1
for count in range(800):
    turtle.width(random.randint(2, 15))
    turtle.speed(200)
    turtle.forward(length)
    turtle.right(135)
    turtle.left(2)
    turtle.color(Faker().hex_color())
    length = length + 15

注： turtle.width() - 定义画笔的大小

如何 "hold" 随机生成颜色？

How do I "hold" the randomly generated color?

random

lambda

colors

turtle-graphics

python-2.7