Apache Camel Swagger - 使用 JPA 实体作为休息类型

Question

我有这个 Rest-DSL：

// this api creates new user
rest("/user")
    .post()
    .type(User.class).to("jpa://com.project.User")

这是我的实体：

public class User{
    @Id
    private String id;
    @ManyToOne
    @JoinColumn(name = "id_role")
    private Role role;
}

public class Role{
    @Id
    private String id;
    @OneToMany(mappedBy="user")
    private List<User> users;
}

我的问题出在我在 Body 值参数示例中的招摇上。它包含这样的内容：

{
  "id": "string",
  "role": {
    "id": "string",
    "users": [
      {
        "id": "string",
        "roles": [
          {}
        ]
      }
    ]
  }
}

相当复杂，虽然我只需要 id 和 id_role 参数来创建 (POST) 新用户。我希望正文示例显示如下：

{
  "id": "string",
  "id_role": "string" 
}

Answer 1

我意识到我的实体创建不正确。这些是我学到的：

Configure CascadeType in associated JPA entities

@Entity

public class User {
    @Id
    private String id;
    @ManyToOne
    @JoinColumn(name = "id_role")
    private Role role;
}

@Entity
public class Role{
    @Id
    private String id;
    @OneToMany(mappedBy="user", cascade = CascadeType.ALL)
    private List<User> users;
}

使class不递归，设置@JsonIgnore

@Entity
@JsonIdentityInfo(
      generator = ObjectIdGenerators.PropertyGenerator.class, 
      property = "id")
public class User{
    @Id
    private String id;
    @ManyToOne
    @JoinColumn(name = "id_role")
    private Role role;
}

@Entity
@JsonIdentityInfo(
      generator = ObjectIdGenerators.PropertyGenerator.class, 
      property = "id")
public class Role{
    @Id
    private String id;
    @OneToMany(mappedBy="user", cascade = CascadeType.ALL)
    @JsonIgnore
    // this attribute will not appear inside Role class
    private List<User> users;
}

Apache Camel Swagger - 使用 JPA 实体作为休息类型

Apache Camel Swagger - using JPA entity as rest type

jpa

apache-camel

swagger

swagger-ui