用 Ansible 替换配置行

Question

文件:

app.php

描述：

我想将第 11 行替换为：

$kernel = new AppKernel('dev', true);

而不是：

$kernel = new AppKernel('prod', false);

main.yml 文件:

我正在尝试这样做，但行不通：

- name: Change to Symfony development enviroment for reflect the changes directly on the vagrant box replace: dest=/vagrant/symfony-standard/web/app.php regexp='$kernel = new AppKernel('prod', false);' replace='$kernel = new AppKernel('dev', true);' backup=yes

航站楼：

TASK [symfony-standard : Change to Symfony development enviroment for reflect the changes directly on the vagrant box] *** task path: /vagrant/playbooks/roles/symfony-standard/tasks/main.yml:49 ok: [default] => {"changed": false, "msg": ""}

Answer 1

我认为你需要转义 $ 符号，尝试这样做：

- name:  Change to Symfony development enviroment for reflect the changes directly on the vagrant box
  replace:
    dest: /vagrant/symfony-standard/web/app.php
    regexp: $kernel = new.*$
    replace: $kernel = new AppKernel('dev', true);

请也试试这个：

$kernel = new AppKernel\('prod', false\);

用 Ansible 替换配置行

Replace configuration line with Ansible

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linux

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vagrant

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