如何为数据框应用grepl

Question

我想将 grepl 用于定义为数据框的多个模式。 df_sen 显示为

sentence
"She would like to go there"
"I had it few days ago"
"We have spent few millions"

df_triggers呈现如下：

trigger
few days
few millions

我想创建一个矩阵，其中句子 x 触发并在交叉点上查看 1 是否在句子中找到触发，如果没有则 0。

我试过这样做：

matrix <- grepl(df_triggers$trigger, df_sen$sentence)

但是我看到错误消息说我在 grepl() 中有超过 1 个模式。

期望的输出是：

                                 few days    few millions
"She would like to go there"        0              0
"I had it few days ago"             1              0
"We have spent few millions         0              1

Answer 1

sapply(df_triggers$trigger, grepl, df_sen$sentence)

来自@docendodiscimus 工作。