Python 2.7 分割线无法通过尾随反斜杠分割

Python 2.7 splitlines fails to split over trailing backslash

使用 Python 2.7.9,我尝试采用 DOS 风格的目录列表,并使用内置的 splitlines 函数将其拆分为单独的行。该清单是一个目录,我的三重引号字符串中的一行包含尾随反斜杠。问题是没有拆分以反斜杠结尾的行:

# DOS-style listing of the directory "B:\"
listing = """Directory of B:\
            12/15/2014  02:12 PM             1814814 BIRD.LOG
            01/01/2000  12:04 AM    <DIR>            CONFIG
            12/15/2014  02:55 PM               35060 ALLIGATOR.LOG
            03/15/2013  02:06 PM    <DIR>            MONKEY
            03/15/2013  02:06 PM    <DIR>            FROG
            03/15/2013  02:06 PM    <DIR>            BADGER
                2 File(s)    1849874 bytes
                4 Dir(s)     1674739712 bytes free
"""

# BIRD.LOG is combined with prior line ending in a backslash
print "keepends = False"
for line in listing.splitlines(False): print repr(line)

# Setting keepends=True does not help
print "keepends = True"
for line in listing.splitlines(True): print repr(line)

这是输出:

keepends = False
'Directory of B:          12/15/2014  02:12 PM             1814814 BIRD.LOG'
'          01/01/2000  12:04 AM    <DIR>            CONFIG'
'          12/15/2014  02:55 PM               35060 ALLIGATOR.LOG'
'          03/15/2013  02:06 PM    <DIR>            MONKEY'
'          03/15/2013  02:06 PM    <DIR>            FROG'
'          03/15/2013  02:06 PM    <DIR>            BADGER'
'              2 File(s)    1849874 bytes'
'              4 Dir(s)     1674739712 bytes free'
keepends = True
'Directory of B:          12/15/2014  02:12 PM             1814814 BIRD.LOG\n'
'          01/01/2000  12:04 AM    <DIR>            CONFIG\n'
'          12/15/2014  02:55 PM               35060 ALLIGATOR.LOG\n'
'          03/15/2013  02:06 PM    <DIR>            MONKEY\n'
'          03/15/2013  02:06 PM    <DIR>            FROG\n'
'          03/15/2013  02:06 PM    <DIR>            BADGER\n'
'              2 File(s)    1849874 bytes\n'
'              4 Dir(s)     1674739712 bytes free\n'

问题不变通过keepends = TruePython splitlines documentation does not mention any special handling of backslashes, and neither does the documentation for the universal newlines approach 分割线。

我的代码示例来自单元测试,但在现实世界中,列表将以编程方式检索。我可以想到涉及操纵我的输入列表或其他方法的解决方法,但我想知道为什么根本不需要解决方法。这是一个错误吗?如果有任何建议,我们将不胜感激!

您的单元测试的问题是字符串文字中的 \ 字符被 Python 解释为转义字符。尝试将第一行更改为

listing = r"""Directory of B:\

来自Python docs

String literals may optionally be prefixed with a letter 'r' or 'R'; such strings are called raw strings and use different rules for interpreting backslash escape sequences.

在从命令输出中获取字符串的实际工作场景中,这应该不是问题。