sed

Question

删除匹配模式后的 "n" 行很容易，使用类似的东西：

IFM_MOUNT="/opt/insiteone/fuse-mount2/ifm"
sed -i "\|$IFM_MOUNT|,+6 d" smb.conf (deletes lines matching and next 6 lines)

但我的问题是，我也想删除匹配模式之前的 2 行。

如何实现？我将调用该命令的文件是一个 Samba 配置文件，如下所示：

[DCCAArchive1]
        comment = DCCA Archive File System
        path = /opt/insiteone/fuse-mount1/ifm
        read only = No
        public = yes
        case sensitive = yes
        writable = yes
        create mask=0777
        guest ok = Yes

[DCCAArchive2]
        comment = DCCA Archive File System
        path = /opt/insiteone/fuse-mount2/ifm
        read only = No
        public = yes
        case sensitive = yes
        writable = yes
        create mask=0777
        guest ok = Yes

[DCCAArchive3]
        comment = DCCA Archive File System
        path = /opt/insiteone/fuse-mount3/ifm
        read only = No
        public = yes
        case sensitive = yes
        writable = yes
        create mask=0777
        guest ok = Yes

Answer 1

您使用以下 sed 命令：

sed -r ':a;N;s~([^\n]*\n){2}[^\n]*'"$search"'\n~~;ba' file

该命令基本上是一个循环。 :a 在循环开始处标记一个标签。 N 读取下一行输入并将其附加到模式缓冲区。 s~([^\n]+\n){2}PATTERN\n~~ 将删除模式和它之前的两行。请注意，我使用 ~ 作为分隔符，因为输入数据包含 "standard" 分隔符 /。 ba 将分支回到循环的开始。在输入结束时，修改后的文件被打印 $p.

顺便说一句，只需将搜索模式中的 2 更改为您想要的任何内容，即可将模式更改为任意数量的前几行。

Answer 2

正如我评论的那样，如果格式是固定的（数据块之间的空行），这一行就可以完成工作：

awk -v RS="" '!/PATTERN/' input

如果不是这种情况，你可以试试这个 awk 单行代码：

awk '{a[NR]=[=11=]}/PATTERN/{for(i=NR-2;i<=NR+6;i++)d[i]=1}
     END{for(i=1;i<=NR;i++)if(!d[i])print a[i]}' input

一个测试

与 ifm 简化 PATTERN
"data blocks"

遵循您的规则：删除行 hit-2 -> hit+6

kent$  cat f
fooooooooo
[DCCAArchive1]
        comment = DCCA Archive File System
        path = /opt/insiteone/fuse-mount1/ifm
        read only = No
        public = yes
        case sensitive = yes
        writable = yes
        create mask=0777
        guest ok = Yes
barrrrrrrrrrrr
[DCCAArchive2]
        comment = DCCA Archive File System
        path = /opt/insiteone/fuse-mount2/ifm
        read only = No
        public = yes
        case sensitive = yes
        writable = yes
        create mask=0777
        guest ok = Yes

kent$  awk  '{a[NR]=[=12=]}/ifm/{for(i=NR-2;i<=NR+6;i++)d[i]=1}END{for(i=1;i<=NR;i++)if(!d[i])print a[i]} ' f
fooooooooo
barrrrrrrrrrrr

编辑

使用来自 shell 变量的模式：

kent$  PAT="/fuse-mount2/ifm"

kent$  awk -v p="$PAT" '{a[NR]=[=13=]}{if(match([=13=],p)>0){for(i=NR-2;i<=NR+6;i++)d[i]=1}}END{for(i=1;i<=NR;i++)if(!d[i])print a[i]} ' f                                          
fooooooooo
[DCCAArchive1]
        comment = DCCA Archive File System
        path = /opt/insiteone/fuse-mount1/ifm
        read only = No
        public = yes
        case sensitive = yes
        writable = yes
        create mask=0777
        guest ok = Yes
barrrrrrrrrrrr

sed - 删除匹配模式前后的 n 行

sed - deleting n lines preceeding and following the matching pattern

linux

编辑