如何在不刷新 reactjs 的情况下更新、重新加载和 ajax table

how can I update, reloads and ajax the table without refreshing reactjs

我很难更新 table 它只在刷新时更新 我不知道我哪里出错了 它只是碰巧我尝试调试它但它读取数据但它只在刷新时更新

 handleUpdate(id, name, address,department,idx){ 

debugger
    const data = {
      'Employee_ID': id,
      'Employee_Name': name,
      'Address': address,
      'Department': department
    }
return fetch('http://localhost:5118/api/employeedetails/PutEmployeeDetail/'+id, {
       method: 'POST',
       headers: {'Content-Type': 'application/json'},
       body: JSON.stringify(data) })
      .then(function(response) {
      console.log(response)
        return response.json();
         this.forceUpdate();
          var jsonReturnedValue = [...this.state.jsonReturnedValue];
        jsonReturnedValue.setState({data:response});
        this.setState({jsonReturnedValue})

      })
      .then((result)=> {    
       })
      .catch(function(error) {
        console.log(error);
      }) 

}

这可能会解决问题。您在 console.log 语句之后使用了 return 语句,这会阻止代码的执行并且不使用 jsonReturnedValue.setState({data:response});

handleUpdate(id, name, address,department,idx){ 

debugger
    const data = {
      'Employee_ID': id,
      'Employee_Name': name,
      'Address': address,
      'Department': department
    }
       return 
       fetch('http://localhost:5118/api/employeedetails/PutEmployeeDetail/'+id, 
       {
       method: 'POST',
       headers: {'Content-Type': 'application/json'},
       body: JSON.stringify(data) })
      .then(function(response) {
      console.log(response)
        this.forceUpdate();
        var jsonReturnedValue = [...this.state.jsonReturnedValue];
        this.setState({jsonReturnedValue});
        return response.json();

      })
      .then((result)=> {    
       })
      .catch(function(error) {
        console.log(error);
      }) 

}

根据我的理解如何ajax 首次安装

npm i jquery -s

然后导入 jQuery

Import $ from 'jQuery';

然后在您的 componentDidMount 中执行 ajax 并执行与您的 componentDidMount

类似的功能
componentDidMount() {
  $.ajax({
  url:'http://localhost:5118/api/employeedetails/getemployeedetails/',
  success:(data)=>{
    this.setState({
      jsonReturnedValue:data
    })
  }
})
}

类似这样的东西

restartFunc(){
   $.ajax({
  url:'http://localhost:5118/api/employeedetails/getemployeedetails/',
  success:(data)=>{
    this.setState({
      jsonReturnedValue:data
    })
  }
})
}

然后将它调用到更新中的 onclick

handleUpdate(id, name, address,department,idx){ 
    const data = {
      'Employee_ID': id,
      'Employee_Name': name,
      'Address': address,
      'Department': department
    }
return fetch('http://localhost:5118/api/employeedetails/PutEmployeeDetail/'+id, {
       method: 'POST',
       headers: {'Content-Type': 'application/json'},
       body: JSON.stringify(data) })
      .then(function(response) {
      })
       .then((result)=> {   
           this.restartFunc()
       })
      .catch(function(error) {
        console.log(error);
      }) 
this.setState({})
}