Java 8 Lambda:比较器

Java 8 Lambda: Comparator

我想用 Lambda 对列表进行排序:

List<Message> messagesByDeviceType = new ArrayList<Message>();      
messagesByDeviceType.sort((Message o1, Message o2)->o1.getTime()-o2.getTime());

但是我得到了这个编译错误:

 Multiple markers at this line
    - Type mismatch: cannot convert from long to int
    - The method sort(Comparator<? super Message>) in the type List<Message> is not applicable for the arguments ((Message o1, Message o2) 
     -> {})

Comparatorcompare() 方法必须 return 一个 int,你的似乎是 return 一个 long

您可以将其更改为:

(Message o1, Message o2)->Long.compare(o1.getTime(),o2.getTime())

这是假设(根据您的错误消息)o1.getTime() return 是 long

Comparator#compareToreturns一个int;而 getTime 显然是 long.

这样写比较好:

.sort(Comparator.comparingLong(Message::getTime))

拉姆达

lambda可以看做是shorthand有点笨重的匿名class:

Java8版本:

Collections.sort(list, (o1, o2) -> o1.getTime() - o2.getTime());

Java8 之前的版本:

    Collections.sort(list, new Comparator<Message>() {
        @Override
        public int compare(Message o1, Message o2) {
            return o1.getTime() - o2.getTime();
        }
    }); 

因此,每当您对如何编写正确的 lambda 感到困惑时,您可以尝试编写一个 pre-lambda 版本,看看它是如何错误的。

申请

在你的具体问题中,你可以看到compare returns int,其中你的getTime returns long,这是错误的来源.

您可以使用任何一种方法作为其他回答方法,例如:

Long.compare(o1.getTime(),o2.getTime())

通知

  • 您应该避免在 Comparator 中使用 -,这在某些情况下可能会导致溢出并导致程序崩溃。

比较器

我们使用比较器接口对同类和异类元素进行默认的自定义排序顺序。

int compare(T o1, T o2);

it takes two arguments for ordering. Returns a

    negative integer(-1) « if first argument is less than the other
    zero             (0) « if both are equal
    positive integer (1) « if first greater than the second.

Anonymous Classes how to sort a list of objects in prior versions of Java 8 使用内部 类.

匿名 class 无法访问其封闭范围内未声明为 final 或有效 final 的局部变量。

Comparator<Employee> timeCompare = new Comparator<Employee>() {
    @Override public int compare(Employee e1, Employee e2) {
        return e1.getCreationTime().compareTo( e2.getCreationTime() );
    }
};

Java 8 Lambda Expressions 使用比较方法

A lambda expression is like a method: it provides a list of formal parameters and a body - an expression or block - expressed in terms of those parameters.

LambdaExpression: LambdaParameters -> LambdaBody

Any local variable, formal parameter, or exception parameter used but not declared in a lambda expression must either be declared final or be effectively final, or a compile-time error occurs where the use is attempted.

Comparator<Employee> functional_semantics = (e1, e2) -> {
   return e1.getCreationTime().compareTo( e2.getCreationTime() );
};

具有 Lambda 支持的基本排序

Comparator<Employee> timeCompareLambda = (o1, o2) -> (int) ( o1.getCreationTime() - o2.getCreationTime());
Collections.sort(java8, timeCompareLambda );

使用提取的密钥和Comparing method通过提取的密钥进行比较的比较器。使用 :: 关键字传递引用。

static <T> Comparator<T> comparingLong(ToLongFunction<? super T> keyExtractor)
ToLongFunction<Employee> keyExtracor = Employee::getCreationTime;
Comparator<Employee> byTime = Comparator.comparingLong( Employee::getCreationTime );

示例测试代码:

public class Lambda_Long_Comparator {
    public static void main(String[] args) {

        List<Employee> java7 = getEmployees();

        // Sort with Inner Class
        Comparator<Employee> timeCompare = new Comparator<Employee>() {
            @Override public int compare(Employee e1, Employee e2) {
                return e1.getCreationTime().compareTo( e2.getCreationTime() );
            }
        };

        // Collections.sort(list); // Defaults to Comparable<T> « @compareTo(o1)
        Collections.sort(java7, timeCompare); // Comparator<T> « @compare (o1,o2)
        System.out.println("Java < 8 \n"+ java7);

        List<Employee> java8 = getEmployees();
        Collections.sort(java8, Comparator
                .comparing( Employee::getCreationTime )
                .thenComparing( Employee::getName ));
        //java8.forEach((emp)-> System.out.println(emp));
        System.out.println("Java 8 \n"+java8);
    }

    static List<Employee> getEmployees() {
        Date date = Calendar.getInstance().getTime();
        List<Employee> list = new ArrayList<Employee>();
        list.add( new Employee(4, "Yash", date.getTime()+7));
        list.add( new Employee(2, "Raju", date.getTime()+1));
        list.add( new Employee(4, "Yas", date.getTime()));
        list.add( new Employee(7, "Sam", date.getTime()-4));
        list.add( new Employee(8, "John", date.getTime()));
        return list;
    }
}
class Employee implements Comparable<Employee> {
    Integer id;
    String name;
    Long creationTime;

    public Employee(Integer id, String name, Long creationTime) {
        this.id = id;
        this.name = name;
        this.creationTime = creationTime;
    }

    @Override public int compareTo(Employee e) {
        return this.id.compareTo(e.id);
    }

    @Override public String toString() {
        return "\n["+this.id+","+this.name+","+this.creationTime+"]";
    }

    // Other getter and setter methods
}

另请参阅这些帖子:

  • Java 8 Tutorial
  • Java8 Lambdas vs Anonymous classes
  • Lambda vs anonymous inner class performance

你应该改变

 messagesByDeviceType.sort(
     (Message o1, Message o2) -> o1.getTime() - o2.getTime()
 );

messagesByDeviceType.sort(
    Comparator.comparing((Message m) -> m.getTime())
);

假定值为 Comparable,这提供了自然排序顺序。

如果您想添加更多字段,则可以将它们链接到比较器。例如先按时间排序,再按发件人排序:

messagesByDeviceType.sort(
    Comparator
        .comparing((Message m) -> m.getTime())
        .thenComparing((m)     -> m.getSender())
);

要反转任何 Comparator 的顺序,请将 reveresed() 方法链接到它,例如首先按时间降序排序,然后按发件人排序:

messagesByDeviceType.sort(
    Comparator
        .comparing((Message m) -> m.getTime())
        .reversed()
        .thenComparing((m)     -> m.getSender())
);

另见 https://docs.oracle.com/javase/8/docs/api/java/util/Comparator.html

compare() 方法必须 return 一个 int,你的方法似乎是 returning long

您可以将其更改为:

Long.compare(o1.getTime(),o2.getTime())

在下面的视频中很好地解释了 lambda 比较器 link

lamda 比较器

In the place of Developer write your class name 

    Comparator<Developer> byName = 
        (Developer o1, Developer o2)->o1.getName().compareTo(o2.getName());