移动图像时如何动态创建文件夹?

How can I create folder dynamically when moving image?

我用laravel 5.3

我的代码是这样移动图像的:

private function savePhoto($photos, $id)
{
    foreach($photos as $key => $photo) {
        $temp = storage_path() . DIRECTORY_SEPARATOR . 'temp' . DIRECTORY_SEPARATOR . $photo['name'];
        $destinationPath = public_path() . DIRECTORY_SEPARATOR . 'img'. DIRECTORY_SEPARATOR .'products'.DIRECTORY_SEPARATOR.$id.DIRECTORY_SEPARATOR.$photo['name'];
        if( rename( $temp , $destinationPath )){
            echo 'moved!';
        } 
        else {
            echo 'failed';
        }
    }
}

执行时出现如下错误:

rename(C:\xampp\htdocs\myshop\storage\temp\NOTFCjMipXwFhBICo1tj6VXP5Qhv92Fg1kmawcUd.jpeg,C:\xampp\htdocs\myshop\public\img\products\NOTFCjMipXwFhBICo1tj6VXP5Qhv92Fg1kmawcUd.jpeg): The system cannot find the path specified. (code: 3)

我认为错误发生是因为 $id 文件夹是动态生成的。 $id 文件夹取决于参数 id。如果参数id = 77,那么会这样构成:

C:\xampp\htdocs\myshop\public\img\products\NOTFCjMipXwFhBICo1tj6VXP5Qhv92Fg1kmawcUd.jpeg

所以出现错误是因为文件夹77还不存在

如何在移动图像之前先创建文件夹77(这是动态生成的)?

更新

来自 $photos 的示例数组结果如下:

Array
(
    [0] => Array
        (
            [id] => 1
            [name] => vYcHWLXpwhC9WfXd4XCB2emg83WMtWHphyUBq9MV.jpeg
        )

    [1] => Array
        (
            [id] => 2
            [name] => 1STr51oF8cunSsNEJZyS9upI0hNHYMXjLCCSNonz.jpeg
        )

)

使用mkdir()

private function savePhoto($photos, $id)
{
    foreach ($photos as $key => $photo) {
        $temp = storage_path() . DIRECTORY_SEPARATOR . 'temp' . DIRECTORY_SEPARATOR . $photo['name'];

        $idDir = public_path() . DIRECTORY_SEPARATOR . 'img' . DIRECTORY_SEPARATOR . 'products' . DIRECTORY_SEPARATOR . $id;
        $destinationPath = $idDir . DIRECTORY_SEPARATOR . $photo['name'];

        if (!is_dir($idDir)) {
            mkdir($idDir, 0777, TRUE);
        }

        if (rename($temp, $destinationPath)) {
            echo 'moved!';
        } else {
            echo 'failed';
        }
    }
}