合并排序实现未按预期工作
Merge Sort implementation not working as expected
我一直在尝试实现归并排序;但不知何故实现是不正确的——输出包含不属于原始数组的值。我试过将它与其他人的实施(工作)进行比较,但似乎找不到错误。
密码是:-
#include <iostream>
using namespace std;
void Merge (int A[], int lo, int hi, int mid){
int i = lo;
int k = 0;
int j = mid+1;
int R[hi-lo];
while(i<=mid && j<=hi){
if(A[i]<A[j]){
R[k]=A[i];
cout << A[i] << "; " << A[j] << " " << i << " " << j << endl;
i++;
}else {
R[k]=A[j];
cout << A[i] << "; " << A[j] << " " << i << " " << j << endl;
j++;
}k++;
}
while(i<=lo){
R[k]=R[i];
i++;k++;
}
while(j<=hi){
R[k]=R[j];
j++;k++;
}
int count =0;
for(i=lo; i<hi; i++){
A[i]=R[count];
count++;
cout << count << " ; " << i << "-/-/-/-/-/-/-" << flush;
}
}
void mergeSort(int A[], int lo, int hi){
//if(hi-lo+1<2)return;
if (lo<hi){
int mid = (lo+hi)/2;
mergeSort(A, lo, mid);
mergeSort(A, mid+1, hi);
Merge (A, lo, hi, mid);}
}
int main(){
int A[] = {1,5,3,4,8,9,150,7,51,65};
int hi = sizeof(A)/sizeof(int);
cout << hi << endl;
mergeSort(A,0, hi);
cout << endl << endl << endl << endl;
for(int i=0; i<=hi; i++){
cout<<A[i]<< "; " << flush;
}
return 0;
}
我试图搜索类似的 Q(S),但找不到。
您的实施问题是边界包含和错误数组的混合。
首先,查看合并中最后的 2 个 while 循环,您做了:R[k]=R[i];
当您的意思是 R[k]=A[i];
在同一个函数上,你的 for 循环缺少一个迭代,循环守卫应该是 i<=hi
而不是 i<hi
。
hi的初始化也是错误的,因为你初始化的是元素个数而不是最后一个索引,你应该减去-1。
我也不知道你的打印代码在做什么,所以我注释掉并添加了我自己的代码,我发现它更清楚。
我更正了你的代码如下:
#include <iostream>
using namespace std;
void Merge (int A[], int lo, int hi, int mid){
int i = lo;
int k = 0;
int j = mid+1;
int R[hi-lo];
cout << "input" << endl;
for(int i=lo; i<=mid; i++)
cout << A[i] << " ";
cout << endl;
for(int i=mid+1; i<=hi; i++)
cout << A[i] << " ";
cout << endl;
while(i<=mid && j<=hi){
if(A[i]<A[j]){
R[k]=A[i];
//cout << A[i] << "; " << A[j] << " " << i << " " << j << endl;
i++;
}else {
R[k]=A[j];
//cout << A[i] << "; " << A[j] << " " << i << " " << j << endl;
j++;
}k++;
}
while(i<=mid){
R[k]=A[i];
i++;k++;
}
while(j<=hi){
R[k]=A[j];
j++;k++;
}
int count =0;
for(i=lo; i<=hi; i++){
A[i]=R[count];
count++;
//cout << count << " ; " << i << "-/-/-/-/-/-/-" << flush;
}
cout << "output:" << endl;
for(int i=lo; i<=hi; i++)
cout << A[i] << " ";
cout << endl;
}
void mergeSort(int A[], int lo, int hi){
//if(hi-lo+1<2)return;
if (lo<hi){
int mid = (lo+hi)/2;
mergeSort(A, lo, mid);
mergeSort(A, mid+1, hi);
Merge (A, lo, hi, mid);}
}
int main(){
int A[] = {1,5,3,4,8,9,150,7,51,65};
int hi = sizeof(A)/sizeof(int) -1;
cout << hi << endl;
mergeSort(A,0, hi);
cout << endl << endl << endl << endl;
for(int i=0; i<=hi; i++){
cout<<A[i]<< "; " << flush;
}
return 0;
}
我一直在尝试实现归并排序;但不知何故实现是不正确的——输出包含不属于原始数组的值。我试过将它与其他人的实施(工作)进行比较,但似乎找不到错误。
密码是:-
#include <iostream>
using namespace std;
void Merge (int A[], int lo, int hi, int mid){
int i = lo;
int k = 0;
int j = mid+1;
int R[hi-lo];
while(i<=mid && j<=hi){
if(A[i]<A[j]){
R[k]=A[i];
cout << A[i] << "; " << A[j] << " " << i << " " << j << endl;
i++;
}else {
R[k]=A[j];
cout << A[i] << "; " << A[j] << " " << i << " " << j << endl;
j++;
}k++;
}
while(i<=lo){
R[k]=R[i];
i++;k++;
}
while(j<=hi){
R[k]=R[j];
j++;k++;
}
int count =0;
for(i=lo; i<hi; i++){
A[i]=R[count];
count++;
cout << count << " ; " << i << "-/-/-/-/-/-/-" << flush;
}
}
void mergeSort(int A[], int lo, int hi){
//if(hi-lo+1<2)return;
if (lo<hi){
int mid = (lo+hi)/2;
mergeSort(A, lo, mid);
mergeSort(A, mid+1, hi);
Merge (A, lo, hi, mid);}
}
int main(){
int A[] = {1,5,3,4,8,9,150,7,51,65};
int hi = sizeof(A)/sizeof(int);
cout << hi << endl;
mergeSort(A,0, hi);
cout << endl << endl << endl << endl;
for(int i=0; i<=hi; i++){
cout<<A[i]<< "; " << flush;
}
return 0;
}
我试图搜索类似的 Q(S),但找不到。
您的实施问题是边界包含和错误数组的混合。
首先,查看合并中最后的 2 个 while 循环,您做了:R[k]=R[i];
当您的意思是 R[k]=A[i];
在同一个函数上,你的 for 循环缺少一个迭代,循环守卫应该是 i<=hi
而不是 i<hi
。
hi的初始化也是错误的,因为你初始化的是元素个数而不是最后一个索引,你应该减去-1。
我也不知道你的打印代码在做什么,所以我注释掉并添加了我自己的代码,我发现它更清楚。
我更正了你的代码如下:
#include <iostream>
using namespace std;
void Merge (int A[], int lo, int hi, int mid){
int i = lo;
int k = 0;
int j = mid+1;
int R[hi-lo];
cout << "input" << endl;
for(int i=lo; i<=mid; i++)
cout << A[i] << " ";
cout << endl;
for(int i=mid+1; i<=hi; i++)
cout << A[i] << " ";
cout << endl;
while(i<=mid && j<=hi){
if(A[i]<A[j]){
R[k]=A[i];
//cout << A[i] << "; " << A[j] << " " << i << " " << j << endl;
i++;
}else {
R[k]=A[j];
//cout << A[i] << "; " << A[j] << " " << i << " " << j << endl;
j++;
}k++;
}
while(i<=mid){
R[k]=A[i];
i++;k++;
}
while(j<=hi){
R[k]=A[j];
j++;k++;
}
int count =0;
for(i=lo; i<=hi; i++){
A[i]=R[count];
count++;
//cout << count << " ; " << i << "-/-/-/-/-/-/-" << flush;
}
cout << "output:" << endl;
for(int i=lo; i<=hi; i++)
cout << A[i] << " ";
cout << endl;
}
void mergeSort(int A[], int lo, int hi){
//if(hi-lo+1<2)return;
if (lo<hi){
int mid = (lo+hi)/2;
mergeSort(A, lo, mid);
mergeSort(A, mid+1, hi);
Merge (A, lo, hi, mid);}
}
int main(){
int A[] = {1,5,3,4,8,9,150,7,51,65};
int hi = sizeof(A)/sizeof(int) -1;
cout << hi << endl;
mergeSort(A,0, hi);
cout << endl << endl << endl << endl;
for(int i=0; i<=hi; i++){
cout<<A[i]<< "; " << flush;
}
return 0;
}