Roslyn (Lambda) 表达式体 属性 语法
Roslyn (Lambda) Expression Bodied Property Syntax
我编写了一个函数将 LocalDeclaration 转换为全局资源。现在我用 属性 替换每个定义,但我想使用新语法 =>
将其替换为 属性
public PropertyDeclarationSyntax ConvertToResourceProperty(string resouceClassIdentifier, string fieldName, string resourceKey, CSharpSyntaxNode field)
{
var stringType = SyntaxFactory.ParseTypeName("string");
var resourceReturnIdentifier = SyntaxFactory.IdentifierName(resouceClassIdentifier + "." + resourceKey);
var returnResourceStatement = SyntaxFactory.ReturnStatement(resourceReturnIdentifier).NormalizeWhitespace();
var getRescourceBlock = SyntaxFactory.Block(returnResourceStatement);
var getAccessor = SyntaxFactory.AccessorDeclaration(SyntaxKind.GetAccessorDeclaration, getRescourceBlock).WithAdditionalAnnotations(Formatter.Annotation, Simplifier.Annotation);
var propertyDeclaration = SyntaxFactory.PropertyDeclaration(stringType, fieldName).AddModifiers(SyntaxFactory.Token(SyntaxKind.PublicKeyword), SyntaxFactory.Token(SyntaxKind.StaticKeyword)).NormalizeWhitespace();
propertyDeclaration = propertyDeclaration.AddAccessorListAccessors(getAccessor).WithAdditionalAnnotations(Formatter.Annotation);
SyntaxTrivia[] leadingTrivia = field.GetLeadingTrivia().ToArray() ?? new[] { SyntaxFactory.Whitespace("\t") };
return propertyDeclaration.WithTrailingTrivia(SyntaxFactory.Whitespace("\r\n"))
.WithLeadingTrivia(leadingTrivia)
.WithAdditionalAnnotations(Simplifier.Annotation);
}
此代码创建一个 属性,如下所示:
public static string LocalResourceName
{
get{ return Resources.LocalResourceName; }
}
我想让 属性 像这样:
public static string LocalResourceName =>Resources.LocalResourceName;
我不太确定什么会从 syntaxfactory 中创建一个 属性 的表达式?谁能告诉我正确的方法?
在网上搜索后,我找到了一种方法。为什么没有 roslyn 的文档?
public PropertyDeclarationSyntax ConvertToResourceProperty(string resouceClassIdentifier, string fieldName, string resourceKey, CSharpSyntaxNode field)
{
var stringType = SyntaxFactory.ParseTypeName("string");
var resourceClassName = SyntaxFactory.IdentifierName(resouceClassIdentifier);
var resourceKeyName = SyntaxFactory.IdentifierName(resourceKey);
var memberaccess = SyntaxFactory.MemberAccessExpression(SyntaxKind.SimpleMemberAccessExpression, resourceClassName, resourceKeyName);
var propertyLambda = SyntaxFactory.ArrowExpressionClause(memberaccess);
var propertyDeclaration = SyntaxFactory.PropertyDeclaration(new SyntaxList<AttributeListSyntax>(), new SyntaxTokenList(),
stringType, null, SyntaxFactory.Identifier(fieldName), null,
propertyLambda, null, SyntaxFactory.Token(SyntaxKind.SemicolonToken))
.AddModifiers(SyntaxFactory.Token(SyntaxKind.PublicKeyword),
SyntaxFactory.Token(SyntaxKind.StaticKeyword)).WithAdditionalAnnotations(Formatter.Annotation).NormalizeWhitespace();
return propertyDeclaration.WithTrailingTrivia(SyntaxFactory.ElasticCarriageReturnLineFeed)
.WithLeadingTrivia(field.GetLeadingTrivia().ToArray())
.WithAdditionalAnnotations(Simplifier.Annotation);
}
我编写了一个函数将 LocalDeclaration 转换为全局资源。现在我用 属性 替换每个定义,但我想使用新语法 =>
将其替换为 属性 public PropertyDeclarationSyntax ConvertToResourceProperty(string resouceClassIdentifier, string fieldName, string resourceKey, CSharpSyntaxNode field)
{
var stringType = SyntaxFactory.ParseTypeName("string");
var resourceReturnIdentifier = SyntaxFactory.IdentifierName(resouceClassIdentifier + "." + resourceKey);
var returnResourceStatement = SyntaxFactory.ReturnStatement(resourceReturnIdentifier).NormalizeWhitespace();
var getRescourceBlock = SyntaxFactory.Block(returnResourceStatement);
var getAccessor = SyntaxFactory.AccessorDeclaration(SyntaxKind.GetAccessorDeclaration, getRescourceBlock).WithAdditionalAnnotations(Formatter.Annotation, Simplifier.Annotation);
var propertyDeclaration = SyntaxFactory.PropertyDeclaration(stringType, fieldName).AddModifiers(SyntaxFactory.Token(SyntaxKind.PublicKeyword), SyntaxFactory.Token(SyntaxKind.StaticKeyword)).NormalizeWhitespace();
propertyDeclaration = propertyDeclaration.AddAccessorListAccessors(getAccessor).WithAdditionalAnnotations(Formatter.Annotation);
SyntaxTrivia[] leadingTrivia = field.GetLeadingTrivia().ToArray() ?? new[] { SyntaxFactory.Whitespace("\t") };
return propertyDeclaration.WithTrailingTrivia(SyntaxFactory.Whitespace("\r\n"))
.WithLeadingTrivia(leadingTrivia)
.WithAdditionalAnnotations(Simplifier.Annotation);
}
此代码创建一个 属性,如下所示:
public static string LocalResourceName
{
get{ return Resources.LocalResourceName; }
}
我想让 属性 像这样:
public static string LocalResourceName =>Resources.LocalResourceName;
我不太确定什么会从 syntaxfactory 中创建一个 属性 的表达式?谁能告诉我正确的方法?
在网上搜索后,我找到了一种方法。为什么没有 roslyn 的文档?
public PropertyDeclarationSyntax ConvertToResourceProperty(string resouceClassIdentifier, string fieldName, string resourceKey, CSharpSyntaxNode field)
{
var stringType = SyntaxFactory.ParseTypeName("string");
var resourceClassName = SyntaxFactory.IdentifierName(resouceClassIdentifier);
var resourceKeyName = SyntaxFactory.IdentifierName(resourceKey);
var memberaccess = SyntaxFactory.MemberAccessExpression(SyntaxKind.SimpleMemberAccessExpression, resourceClassName, resourceKeyName);
var propertyLambda = SyntaxFactory.ArrowExpressionClause(memberaccess);
var propertyDeclaration = SyntaxFactory.PropertyDeclaration(new SyntaxList<AttributeListSyntax>(), new SyntaxTokenList(),
stringType, null, SyntaxFactory.Identifier(fieldName), null,
propertyLambda, null, SyntaxFactory.Token(SyntaxKind.SemicolonToken))
.AddModifiers(SyntaxFactory.Token(SyntaxKind.PublicKeyword),
SyntaxFactory.Token(SyntaxKind.StaticKeyword)).WithAdditionalAnnotations(Formatter.Annotation).NormalizeWhitespace();
return propertyDeclaration.WithTrailingTrivia(SyntaxFactory.ElasticCarriageReturnLineFeed)
.WithLeadingTrivia(field.GetLeadingTrivia().ToArray())
.WithAdditionalAnnotations(Simplifier.Annotation);
}