为什么在运行复杂查询时出现 "array_map(): Argument #2 should be an array" 错误？

Question

我正在编写过滤器搜索代码，用户从 3 个复选框列表中选择至少一个选项，然后我必须为所选选项（复选框）编写查询。如果我尝试运行我的代码然后我得到 "array_map(): Argument #2 should be an array".

我的表格是：

<form id="statistics" method="post" action="{{ action('MyController@store') }}"">
<div class="form-group">
 <label><input type="checkbox" value="suppliers" name="suppliers">suppliers</label>
</div>
<div class="form-group">
 <label><input type="checkbox" value="campaign" name="campaign">campaign</label>
</div>
<div class="form-group">
 <label><input type="checkbox" value="clients" name="clients">clients</label>
</div>
<div class="form-group">
 <label for="start_date">From:</label><input type="text" name="startdate" id="startdate">
</div>
<div class="form-group">
 <label for="start_date">From:</label><input type="text" name="enddate" id="enddate">
</div>
<div class="form-group">
 <button type="submit" id="process" class="btn btn-primary submit">Run Report</button>
</div>

我的查询如下：

if($request->suppliers == 'suppliers'){
        $results->leftjoin('suppliers AS s', 's.id', '=', 'l.supplier_id')
                ->select('s.name AS Supplier')
                ->groupBy('s.name')
                ->orderBy('s.name');
    }
if($request->campaign == 'campaign'){
        $results->leftjoin('campaigns AS c', 'c.id', '=', 'l.campaign_id')
                ->select('c.name AS Campaign')
                ->groupBy('c.name')
                ->orderBy('c.name');
    }
if($request->clients == 'clients'){
        $results->leftjoin('clients AS cl', 'cl.id', '=', 'l.client_id')
                ->groupBy('cl.name')
                ->orderBy('cl.name');
    }
$results->whereBetween('l.received', [$start, $end])
        ->groupBy('l.disposition')         
        ->orderBy('l.disposition')
        ->get()->toArray();
$count = count($results);
if($count > 0)
{
 $results = array_map(function ($value) {
            return (array)$value;
        }, $results); 
 Excel::create('Statistics', function($excel) use($results) {
            $excel->sheet('Statistics', function($sheet) use($results) {
                $sheet->fromArray($results);
            });
        })->download('csv');
    }

如果我运行上面的代码然后我得到一个像 "array_map(): Argument #2 should be an array"

这样的错误

正常查询正常，如下所示：

$results = DB::table('lead_audit AS l')
         ->leftjoin('suppliers AS s', 's.id', '=', 'l.supplier_id')
         ->leftjoin('campaigns AS c', 'c.id', '=', 'l.campaign_id')
         ->select('s.name AS Supplier', 'c.name AS Campaign', 'l.disposition AS Disposition')
         ->whereBetween('l.received', [$start, $end])
         ->groupBy('s.name', 'c.name', 'l.disposition')
         ->orderBy('s.name')
         ->orderBy('c.name')
         ->orderBy('l.disposition')
         ->get()->toArray();
$count = count($results);

谁能帮我解决这个问题，谢谢。

Answer 1

看起来 $results 只是一个查询而不是数组。您需要更改为以下代码

$queryResults = $results->whereBetween('l.received', [$start, $end])
    ->groupBy('l.disposition')         
    ->orderBy('l.disposition')
    ->get()->toArray();
$count = count($results);
if($count > 0)
{
 $results = array_map(function ($value) {
            return (array)$value;
        }, $results);

到下面的代码

$results->whereBetween('l.received', [$start, $end])
    ->groupBy('l.disposition')         
    ->orderBy('l.disposition')
    ->get()->toArray();
$count = count($results);
if($count > 0)
{
 $results = array_map(function ($value) {
            return (array)$value;
        },$queryResults);

在上面的代码中，我将查询结果分配给变量$queryResults，然后将其传递给array_map功能。

为什么在运行复杂查询时出现 "array_map(): Argument #2 should be an array" 错误？

why getting "array_map(): Argument #2 should be an array" error while running complex query?

mysql

search

filter

laravel-query-builder

laravel-5.4

为什么在 运行 复杂查询时出现 "array_map(): Argument #2 should be an array" 错误？

why getting "array_map(): Argument #2 should be an array" error while running complex query?

mysql

search

filter

laravel-query-builder

laravel-5.4

为什么在运行复杂查询时出现 "array_map(): Argument #2 should be an array" 错误？