是否有可能在 matplotlib 中获得曲线下的颜色渐变？

Question

我碰巧在这个 page 上看到了一个漂亮的图表，如下所示：

是否可以在matplotlib中获得这样的颜色渐变？

Answer 1

之前有一些类似问题的答案（例如），但他们推荐了一种次优的方法。

之前的大多数答案都建议在 pcolormesh 填充上绘制白色多边形。这不太理想，原因有二：

坐标轴的背景不能是透明的，因为上面有一个填充的多边形
pcolormesh 绘制速度相当慢且插值不流畅。

需要做更多的工作，但有一种方法可以更快地绘制并提供更好的视觉效果：设置使用 imshow 绘制的图像的剪辑路径。

举个例子：

import numpy as np
import matplotlib.pyplot as plt
import matplotlib.colors as mcolors
from matplotlib.patches import Polygon
np.random.seed(1977)

def main():
    for _ in range(5):
        gradient_fill(*generate_data(100))
    plt.show()

def generate_data(num):
    x = np.linspace(0, 100, num)
    y = np.random.normal(0, 1, num).cumsum()
    return x, y

def gradient_fill(x, y, fill_color=None, ax=None, **kwargs):
    """
    Plot a line with a linear alpha gradient filled beneath it.

    Parameters
    ----------
    x, y : array-like
        The data values of the line.
    fill_color : a matplotlib color specifier (string, tuple) or None
        The color for the fill. If None, the color of the line will be used.
    ax : a matplotlib Axes instance
        The axes to plot on. If None, the current pyplot axes will be used.
    Additional arguments are passed on to matplotlib's ``plot`` function.

    Returns
    -------
    line : a Line2D instance
        The line plotted.
    im : an AxesImage instance
        The transparent gradient clipped to just the area beneath the curve.
    """
    if ax is None:
        ax = plt.gca()

    line, = ax.plot(x, y, **kwargs)
    if fill_color is None:
        fill_color = line.get_color()

    zorder = line.get_zorder()
    alpha = line.get_alpha()
    alpha = 1.0 if alpha is None else alpha

    z = np.empty((100, 1, 4), dtype=float)
    rgb = mcolors.colorConverter.to_rgb(fill_color)
    z[:,:,:3] = rgb
    z[:,:,-1] = np.linspace(0, alpha, 100)[:,None]

    xmin, xmax, ymin, ymax = x.min(), x.max(), y.min(), y.max()
    im = ax.imshow(z, aspect='auto', extent=[xmin, xmax, ymin, ymax],
                   origin='lower', zorder=zorder)

    xy = np.column_stack([x, y])
    xy = np.vstack([[xmin, ymin], xy, [xmax, ymin], [xmin, ymin]])
    clip_path = Polygon(xy, facecolor='none', edgecolor='none', closed=True)
    ax.add_patch(clip_path)
    im.set_clip_path(clip_path)

    ax.autoscale(True)
    return line, im

main()

Answer 2

请注意应该得到这里的大部分荣誉；我唯一的贡献是 zfunc. 他的方法向许多人敞开了大门 gradient/blur/drop-shadow 效果。例如，要使线条的底面均匀模糊，您可以使用 PIL 构建一个 alpha 层，该层在线附近为 1，底部边缘附近为 0。

import numpy as np
import matplotlib.pyplot as plt
import matplotlib.colors as mcolors
import matplotlib.patches as patches
from PIL import Image
from PIL import ImageDraw
from PIL import ImageFilter

np.random.seed(1977)
def demo_blur_underside():
    for _ in range(5):
        # gradient_fill(*generate_data(100), zfunc=None) # original
        gradient_fill(*generate_data(100), zfunc=zfunc)
    plt.show()

def generate_data(num):
    x = np.linspace(0, 100, num)
    y = np.random.normal(0, 1, num).cumsum()
    return x, y

def zfunc(x, y, fill_color='k', alpha=1.0):
    scale = 10
    x = (x*scale).astype(int)
    y = (y*scale).astype(int)
    xmin, xmax, ymin, ymax = x.min(), x.max(), y.min(), y.max()

    w, h = xmax-xmin, ymax-ymin
    z = np.empty((h, w, 4), dtype=float)
    rgb = mcolors.colorConverter.to_rgb(fill_color)
    z[:,:,:3] = rgb

    # Build a z-alpha array which is 1 near the line and 0 at the bottom.
    img = Image.new('L', (w, h), 0)  
    draw = ImageDraw.Draw(img)
    xy = (np.column_stack([x, y]))
    xy -= xmin, ymin
    # Draw a blurred line using PIL
    draw.line(map(tuple, xy.tolist()), fill=255, width=15)
    img = img.filter(ImageFilter.GaussianBlur(radius=100))
    # Convert the PIL image to an array
    zalpha = np.asarray(img).astype(float) 
    zalpha *= alpha/zalpha.max()
    # make the alphas melt to zero at the bottom
    n = zalpha.shape[0] // 4
    zalpha[:n] *= np.linspace(0, 1, n)[:, None]
    z[:,:,-1] = zalpha
    return z

def gradient_fill(x, y, fill_color=None, ax=None, zfunc=None, **kwargs):
    if ax is None:
        ax = plt.gca()

    line, = ax.plot(x, y, **kwargs)
    if fill_color is None:
        fill_color = line.get_color()

    zorder = line.get_zorder()
    alpha = line.get_alpha()
    alpha = 1.0 if alpha is None else alpha

    if zfunc is None:
        h, w = 100, 1
        z = np.empty((h, w, 4), dtype=float)
        rgb = mcolors.colorConverter.to_rgb(fill_color)
        z[:,:,:3] = rgb
        z[:,:,-1] = np.linspace(0, alpha, h)[:,None]
    else:
        z = zfunc(x, y, fill_color=fill_color, alpha=alpha)
    xmin, xmax, ymin, ymax = x.min(), x.max(), y.min(), y.max()
    im = ax.imshow(z, aspect='auto', extent=[xmin, xmax, ymin, ymax],
                   origin='lower', zorder=zorder)

    xy = np.column_stack([x, y])
    xy = np.vstack([[xmin, ymin], xy, [xmax, ymin], [xmin, ymin]])
    clip_path = patches.Polygon(xy, facecolor='none', edgecolor='none', closed=True)
    ax.add_patch(clip_path)
    im.set_clip_path(clip_path)
    ax.autoscale(True)
    return line, im

demo_blur_underside()

产量

Answer 3

我试过一些东西：

import matplotlib.pyplot as plt
import numpy as np

fig = plt.figure()

xData = range(100)
yData = range(100)
plt.plot(xData, yData)

NbData = len(xData)
MaxBL = [[MaxBL] * NbData for MaxBL in range(100)]
Max = [np.asarray(MaxBL[x]) for x in range(100)]

for x in range (50, 100):
  plt.fill_between(xData, Max[x], yData, where=yData >Max[x], facecolor='red', alpha=0.02)

for x in range (0, 50):
  plt.fill_between(xData, yData, Max[x], where=yData <Max[x], facecolor='green', alpha=0.02)

plt.fill_between([], [], [], facecolor='red', label="x > 50")
plt.fill_between([], [], [], facecolor='green', label="x < 50")

plt.legend(loc=4, fontsize=12)
plt.show()
fig.savefig('graph.png')

.. 结果：

当然，通过改变feel_between函数的范围，梯度可以下降到0。

是否有可能在 matplotlib 中获得曲线下的颜色渐变？

Is it possible to get color gradients under curve in matplotlib?

python

matplotlib