使用 Swashbuckle 记录模型属性
Using Swashbuckle to document model properties
让 swashbuckle 生成传递给操作的各个参数的描述非常容易,但是如果我传递这样的模型:
public void Put([FromUri] ViewModelTest viewModelTest)
{
}
模型看起来像这样:
public class ViewModelTest
{
public int Id { get; set; }
public string Name { get; set; }
}
是否有推荐的填充模型描述的策略?
这是一个工作示例:
http://swashbuckletest.azurewebsites.net/swagger/ui/index#!/TestEnum/TestEnum_Put
代码在 GitHub:
https://github.com/heldersepu/Swagger-Net-Test/blob/master/Swagger_Test/Models/ViewModelTest.cs
public class ViewModelTest
{
/// <summary>
/// The super ID that will be used
/// </summary>
/// <example>123</example>
public int SuperId { get; set; }
/// <summary>
/// Who needs a name?
/// </summary>
/// <example>John Doe</example>
public string Name { get; set; }
...并且在您的 Swagger 配置 (App_Start/SwaggerConfig.cs) 中,您需要启用 IncludeXmlComments
让 swashbuckle 生成传递给操作的各个参数的描述非常容易,但是如果我传递这样的模型:
public void Put([FromUri] ViewModelTest viewModelTest)
{
}
模型看起来像这样:
public class ViewModelTest
{
public int Id { get; set; }
public string Name { get; set; }
}
是否有推荐的填充模型描述的策略?
这是一个工作示例:
http://swashbuckletest.azurewebsites.net/swagger/ui/index#!/TestEnum/TestEnum_Put
代码在 GitHub:
https://github.com/heldersepu/Swagger-Net-Test/blob/master/Swagger_Test/Models/ViewModelTest.cs
public class ViewModelTest
{
/// <summary>
/// The super ID that will be used
/// </summary>
/// <example>123</example>
public int SuperId { get; set; }
/// <summary>
/// Who needs a name?
/// </summary>
/// <example>John Doe</example>
public string Name { get; set; }
...并且在您的 Swagger 配置 (App_Start/SwaggerConfig.cs) 中,您需要启用 IncludeXmlComments