方法等于搜索是否等于两个数字
method equals search if is equal two numbers or not
我想帮助我 this.I 应该创建一个方法 equals 来检查两个 objects.If 对象是否相等然后它将 return 为真,否则它将 return 错误。
对我来说我已经研究过这个但是我以前用不同的方式做了一个方法
public static boolean trueorfalse(int cars,int bikes){
boolean y;
if(get.car==get.bikes)
{
System.out.println("are equal");
y=true;
}
else
{
System.err.println("arent equal");
y=false;
}
return y;
}
现在方法等于:
public static boolean equal(int cars,int bikes){ //i change the name?
if(get.car==get.bikes) // may needs here equalsof() something like this? or is completely wrong i am.
{
System.out.println("are equal");
y=true;
}
else
{
System.err.println("arent equal");
y=false;
}
return y;
}
如果你能帮我解决这个问题,我会很感激,因为我想我已经解决了,但我还没有 sure.Thanks,我想说这是我第一次来这里,我不知道是否因为是 "begginer" 级你帮不上忙。
我想说,你太接近了,无法纠正。
现在,它已修复!
public static boolean equal(int cars,int bikes{
if(car==bikes)
//since you are comparing two ints, you don't require any !
{
System.out.println("are equal");
y=true;
}
else
{
System.err.println("arent equal");
/*Preferably use System.out.println().Having an inequality as this cannot be
attributed to error. It's okay if you stick to your view.There is no hard and fast rule either !*/
y=false;
}
return y;
}
我想帮助我 this.I 应该创建一个方法 equals 来检查两个 objects.If 对象是否相等然后它将 return 为真,否则它将 return 错误。 对我来说我已经研究过这个但是我以前用不同的方式做了一个方法
public static boolean trueorfalse(int cars,int bikes){
boolean y;
if(get.car==get.bikes)
{
System.out.println("are equal");
y=true;
}
else
{
System.err.println("arent equal");
y=false;
}
return y;
}
现在方法等于:
public static boolean equal(int cars,int bikes){ //i change the name?
if(get.car==get.bikes) // may needs here equalsof() something like this? or is completely wrong i am.
{
System.out.println("are equal");
y=true;
}
else
{
System.err.println("arent equal");
y=false;
}
return y;
}
如果你能帮我解决这个问题,我会很感激,因为我想我已经解决了,但我还没有 sure.Thanks,我想说这是我第一次来这里,我不知道是否因为是 "begginer" 级你帮不上忙。
我想说,你太接近了,无法纠正。
现在,它已修复!
public static boolean equal(int cars,int bikes{
if(car==bikes)
//since you are comparing two ints, you don't require any !
{
System.out.println("are equal");
y=true;
}
else
{
System.err.println("arent equal");
/*Preferably use System.out.println().Having an inequality as this cannot be
attributed to error. It's okay if you stick to your view.There is no hard and fast rule either !*/
y=false;
}
return y;
}