如何将乌龟设置为乌龟屏幕

Question

我有一个我正在尝试制作的游戏，但是当我创建我的屏幕和我的乌龟时，我的乌龟出现在与我制作的屏幕不同的屏幕上。如果我要运行代码，它会弹出 2 个不同的乌龟屏幕 A：我称之为屏幕的那个，以及 B：当您创建没有屏幕的乌龟时自动弹出的那个。

import turtle
from turtle import *
from turtle import Screen
import tkinter
from tkinter import *
import time
from time import sleep
from random import randint
import random
health = 50
damage = 10
root = Tk()
Fight = randint(10,20)
step = 0
cv = ScrolledCanvas(root,600,600,600,600)
cv.pack(side = tkinter.LEFT)
turtle = Turtle()
screen = TurtleScreen(cv)
turtle.up()
def Up(event):

    global step
    if step == Fight:
        Combat()
    step+=1
    turtle.seth(90)
    turtle.forward(10)
def Down(event):
    global step
    if step == Fight:
        Combat()
    step+=1
    turtle.seth(-90)
    turtle.forward(10)
def Left(event):
    global step
    if step == Fight:
        Combat()
    step+=1
    turtle.seth(180)
    turtle.forward(10)
def Right(event):
    global step
    if step == Fight:
        Combat()
    step+=1
    turtle.seth(0)
    turtle.forward(10)
def Combat():
    Enemy = Turtle()
    Enemy.up()
    EHealth = randint(20,100)
    EDamage = randint(10,20)



screen.onkey(forward, "Up")
screen.onkey(backward, "Down")
screen.onkey(left, "Left")
screen.onkey(right, "Right")
screen.listen()

谢谢，

Answer 1

Python turtle 被设计为嵌入到您自己制作的 Tk window 或它正在制作的 Tk window 中。这两个选项的调用方式不同，但通过混合命令，您最终会得到两者。采用您开始的自定义 Tk window 方法：

from random import randint
from tkinter import *
from turtle import ScrolledCanvas, RawTurtle, TurtleScreen

health = 50
damage = 10
fight = randint(10, 20)
step = 0

def up():
    global step

    if step == fight:
        combat()
    step += 1
    turtle.seth(90)
    turtle.forward(10)

def down():
    global step

    if step == fight:
        combat()
    step += 1
    turtle.seth(-90)
    turtle.forward(10)

def left():
    global step

    if step == fight:
        combat()
    step += 1
    turtle.seth(180)
    turtle.forward(10)

def right():
    global step

    if step == fight:
        combat()
    step += 1
    turtle.seth(0)
    turtle.forward(10)

def combat():
    enemy = RawTurtle(canvas)
    enemy.up()
    eHealth = randint(20, 100)
    eDamage = randint(10, 20)

root = Tk()
canvas = ScrolledCanvas(root)
canvas.pack(side=LEFT)
screen = TurtleScreen(canvas)
turtle = RawTurtle(canvas)
turtle.up()

screen.onkey(up, "Up")
screen.onkey(down, "Down")
screen.onkey(left, "Left")
screen.onkey(right, "Right")
screen.listen()

screen.mainloop()

或者，我们可以通过让 turtle 模块创建 window 来简化事情，尽管我们可以通过其方法调用根据需要调整它：

from random import randint
from turtle import Turtle, Screen

health = 50
damage = 10
fight = randint(10, 20)
step = 0

def up():
    global step

    if step == fight:
        combat()
    step += 1
    turtle.seth(90)
    turtle.forward(10)

def down():
    global step

    if step == fight:
        combat()
    step += 1
    turtle.seth(-90)
    turtle.forward(10)

def left():
    global step

    if step == fight:
        combat()
    step += 1
    turtle.seth(180)
    turtle.forward(10)

def right():
    global step

    if step == fight:
        combat()
    step += 1
    turtle.seth(0)
    turtle.forward(10)

def combat():
    enemy = Turtle()
    enemy.up()
    eHealth = randint(20, 100)
    eDamage = randint(10, 20)

screen = Screen()
screen.setup(500, 350)  # visible portion of screen area
screen.screensize(600, 600)  # scrollable extent of screen area
turtle = Turtle()
turtle.up()

screen.onkey(up, "Up")
screen.onkey(down, "Down")
screen.onkey(left, "Left")
screen.onkey(right, "Right")
screen.listen()

screen.mainloop()

您在使用 import 时应该更加谨慎，因为以两种不同的方式导入相同的模块最终会使您感到困惑 and/or Python.

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