根据 Results/ID 计算多个字段的最终结果

Question

为此扩展解决方案：

使用相同的业务逻辑，如何获得另一个基于 LA 字段的 Final Result 2 以及基于 Employment 字段的 Final Result？当涉及多个字段时，排名功能显然会有所不同。

Table T1 扩展：

+----------+-----------+-----------------+-----------------+
| PersonID |   Date    |   Employment    |       LA        |
+----------+-----------+-----------------+-----------------+
|        1 | 2/28/2017 | Stayed the same | Improved        |
|        1 | 4/21/2017 | Stayed the same | Stayed the same |
|        1 | 5/18/2017 | Stayed the same | Improved        |
|        2 | 3/7/2017  | Improved        | Stayed the same |
|        2 | 4/1/2017  | Stayed the same | Stayed the same |
|        2 | 6/1/2017  | Stayed the same | Improved        |
|        3 | 3/28/2016 | Improved        | Improved        |
|        3 | 5/4/2016  | Improved        | Improved        |
|        3 | 4/19/2017 | Worsened        | Worsened        |
|        4 | 5/19/2016 | Worsened        | Stayed the same |
|        4 | 2/16/2017 | Improved        | Stayed the same |
+----------+-----------+-----------------+-----------------+

期望输出：

+----------+-----------------+-----------------+
| PersonID |  Final Result   | Final Result 2  |
+----------+-----------------+-----------------+
|        1 | Stayed the same | Improved        |
|        2 | Improved        | Improved        |
|        3 | Worsened        | Worsened        |
|        4 | Improved        | Stayed the same |
+----------+-----------------+-----------------+

Answer 1

添加另一个 RN 应该可行

select t1.personid, t1.employment, t2.LA
from (select t1.*,
                row_number() over (partition by personid
                                order by (case when employment <> 'Stayed the same' then 1 else 2 end),
                                            date desc
                                ) as seqnum
        from t1
        ) t1
left join
    (select t1.PersonID, t1.LA,
                row_number() over (partition by personid
                                order by (case when LA <> 'Stayed the same' then 1 else 2 end),
                                            date desc
                                ) as seqnum
        from t1) t2 on t2.PersonID = t1.PersonID and t2.seqnum = 1
where t1.seqnum = 1

根据 Results/ID 计算多个字段的最终结果

Calculate final outcomes based on Results/ID for multiple fields

sql

sql-server

window

subquery

sql-server-2012