使用 Cloud Functions 从数据库中删除值
Remove value from database using Cloud Functions
我有以下数据结构:
如何使用 Cloud Functions 完全删除 'days'?
我当前的代码:
const functions = require('firebase-functions');
const admin = require('firebase-admin');
admin.initializeApp(functions.config().firebase);
exports.deleteOldItems = functions.database.ref('/path/to/items/{pushId}')
.onWrite(event => {
var ref = event.data.ref.parent; // reference to the items
var now = Date.now();
var cutoff = now - 2 * 60 * 60 * 1000;
var oldItemsQuery = ref.orderByChild('timestamp').endAt(cutoff);
return oldItemsQuery.once('value', function(snapshot) {
// create a map with all children that need to be removed
var updates = {};
snapshot.forEach(function(child) {
updates[child.key] = null
});
// execute all updates in one go and return the result to end the function
return ref.update(updates);
});
functions.database.ref('/days').remove(); // <- /days doesn't get removed
});
您在调用 remove 之前从函数返回。尝试:
return oldItemsQuery.once('value', function(snapshot) {
// create a map with all children that need to be removed
var updates = {};
snapshot.forEach(function(child) {
updates[child.key] = null
});
// execute all updates in one go and return the result to end the function
return ref.update(updates);
}).then(function() {;
return functions.database.ref('/days').remove();
});
我有以下数据结构:
如何使用 Cloud Functions 完全删除 'days'?
我当前的代码:
const functions = require('firebase-functions');
const admin = require('firebase-admin');
admin.initializeApp(functions.config().firebase);
exports.deleteOldItems = functions.database.ref('/path/to/items/{pushId}')
.onWrite(event => {
var ref = event.data.ref.parent; // reference to the items
var now = Date.now();
var cutoff = now - 2 * 60 * 60 * 1000;
var oldItemsQuery = ref.orderByChild('timestamp').endAt(cutoff);
return oldItemsQuery.once('value', function(snapshot) {
// create a map with all children that need to be removed
var updates = {};
snapshot.forEach(function(child) {
updates[child.key] = null
});
// execute all updates in one go and return the result to end the function
return ref.update(updates);
});
functions.database.ref('/days').remove(); // <- /days doesn't get removed
});
您在调用 remove 之前从函数返回。尝试:
return oldItemsQuery.once('value', function(snapshot) {
// create a map with all children that need to be removed
var updates = {};
snapshot.forEach(function(child) {
updates[child.key] = null
});
// execute all updates in one go and return the result to end the function
return ref.update(updates);
}).then(function() {;
return functions.database.ref('/days').remove();
});