如何将 Couchbase 中的数据与 map reduce 合并?
How to merge data in Couchbase with map reduce?
我的应用程序将多种文档类型存储在同一个存储桶中。我知道这不是好的做法,但我对可以在服务器上创建的存储桶数量有限制,目前没有办法解决。这些文档以它们的类型为前缀,所以当我得到一个文档时,我只需要连接前缀和 id 来获取密钥,然后我就可以进行密钥查找。
我需要创建一个报告,从多种文档类型中提取信息。
我的地图是这样的:
function(doc, meta) {
var getStep = function(stepName, exit, mapper) {
if (meta.id.indexOf(stepName) !== -1) {
var hotelId = parseInt(meta.id.replace(stepName + '_', ''));
if (hotelId > 0) {
var result = {
hotelId: hotelId,
exit: exit
};
if (mapper !== undefined) {
mapper(result);
}
return result;
}
}
return null;
};
var photos = getStep('PHOTOS', 7);
if (photos != null) {
emit(photos.hotelId, photos);
}
var pricing = getStep('PICR', 5);
if (pricing != null) {
emit(pricing.hotelId, pricing);
}
var owner = getStep('OWNER', 1);
if (owner != null) {
emit(owner.hotelId, owner);
}
var amenity = getStep('AM', 4);
if (amenity != null) {
emit(amenity.hotelId, amenity);
}
var description = getStep('HDESC', 3, function(result) {
result.description = doc.description;
result.hotelRoomTypeId = doc.hotelRoomTypeId;
result.starRating = doc.starRating;
});
if (description != null) {
emit(description.hotelId, description);
}
var contact = getStep('DC', 3, function(result) {
result.email = doc.emailAddress;
result.contact = doc.mainContactName;
});
if (contact != null) {
emit(contact.hotelId, contact);
}
var location = getStep('LOC', 2, function(result) {
result.city = doc.cityName;
result.zip = doc.postalCode;
result.country = doc.countryName;
result.street = doc.stateName + ', ' + doc.streetName;
});
if (location != null) {
emit(location.hotelId, location);
}
var property = getStep('PRP', 1, function(result) {
result.paymentMethodId = doc.paymentMethodId
});
if (property != null) {
emit(property.hotelId, property);
}
}
它生成此输出:
"total_rows":...,"rows":[
{"id":"DC_1","key":1,"value":{"hotelId":1,"exit":3,"email":"test@example.com","contact":"Jeno"}},
{"id":"HDESC_1","key":1,"value":{"hotelId":1,"exit":3,"description":".","hotelRoomTypeId":0,"starRating":5}},
{"id":"LOC_1","key":1,"value":{"hotelId":1,"exit":2,"city":"Barcelona","zip":"1222","country":"Spain","street":"Catalonia, someplacenice"}},
{"id":"PRP_1","key":1,"value":{"hotelId":1,"exit":1}},
{"id":"PRP_2","key":2,"value":{"hotelId":2,"exit":1}},
{"id":"AM_3","key":3,"value":{"hotelId":3,"exit":4}},
{"id":"AM_4","key":4,"value":{"hotelId":4,"exit":4}},
{"id":"PHOTOS_4","key":4,"value":{"hotelId":4,"exit":7}},
{"id":"PRP_4","key":4,"value":{"hotelId":4"exit":1}},
{"id":"AM_4","key":4,"value":{"hotelId":4,"exit":4}},
{"id":"PRP_4","key":4,"value":{"hotelId":4,"exit":1}},
{"id":"PHOTOS_5","key":5,"value":{"hotelId":5,"exit":7}}
...
]
我正在尝试按新键 hotelId 对日期进行分组,并使用自定义缩减器将字段合并到一个文档中。根据错误类型,我收到不同的错误,但所有错误似乎都表明减速器可以 return 的日期有限制。如果我将 return 类型从一个对象更改为一个关联数组,它的工作方式几乎相同,我会得到一个更好的错误。
function(key, values, rereduce) {
if (rereduce) {
return values;
} else {
var results = {}; // Object!
for (var i = 0; i < values.length; i++) {
var row = values[i];
if (!results[row.hotelId]) {
results[row.hotelId] = {
phone: '',
exit: 1
};
}
var result = results[row.hotelId];
for (var name in row) {
result[name] = row[name];
}
if (row.exit > row.exit) {
result.exit = row.exit;
}
};
return results;
}
}
给我 RangeError: Maximum call stack size exceeded
function(key, values, rereduce) {
if (rereduce) {
return values;
} else {
var results = []; // Array!
for (var i = 0; i < values.length; i++) {
var row = values[i];
if (!results[row.hotelId]) {
results[row.hotelId] = {
phone: '',
exit: 1
};
}
var result = results[row.hotelId];
for (var name in row) {
result[name] = row[name];
}
if (row.exit > row.exit) {
result.exit = row.exit;
}
};
return results;
}
}
给我 reduction too large error
function(key, values, rereduce) {
if (rereduce) {
return values;
} else {
return values;
}
}
给我 RangeError: Maximum call stack size exceeded
如果我运行:
function(key, values, rereduce) {
if (rereduce) {
return values;
} else {
return values.length;
}
}
我回来了:
[ 68, 72, 65, 66, 68, 68, 70, 114 ]
JavaScript 引擎应该能够减少最大 114 大小的数组,输出数据应该更小。显然,reduce 可以 return max_kv_size_per_doc
限制多少数据,即 1Mb,也有 10 秒的执行限制,但在我的例子中是另外一回事。有没有办法通过改变算法来绕过这些限制,returning 数组或数组之类的?我可以在地图上做些什么,或者我可以在 rereduce 中使用一些技巧吗?
我明白了。如果我使用复合键和 group_level,它会起作用。
因此,如果我将地图更改为 return 一个数组作为酒店 ID 的键,并且我设置 group_level = 1 那么这些值将按照我最初的预期为我分组:
function(doc, meta) {
var getStep = function(stepName, exit, mapper) {
if (meta.id.indexOf(stepName) !== -1) {
var hotelId = parseInt(meta.id.replace(stepName + '_', ''));
if (hotelId > 0) {
var result = {
hotelId: hotelId,
exit: exit
};
if (mapper !== undefined) {
mapper(result);
}
return result;
}
}
return null;
};
var photos = getStep('PHOTOS', 7);
if (photos != null) {
emit([photos.hotelId], photos); // array as key
}
var pricing = getStep('PICR', 5); // array as key
if (pricing != null) {
emit([pricing.hotelId], pricing);
}
var owner = getStep('OWNER', 1); // array as key
if (owner != null) {
emit([owner.hotelId], owner);
}
var amenity = getStep('AM', 4); // array as key
if (amenity != null) {
emit([amenity.hotelId], amenity);
}
var description = getStep('HDESC', 3, function(result) {
result.description = doc.description;
result.hotelRoomTypeId = doc.hotelRoomTypeId;
result.starRating = doc.starRating;
});
if (description != null) {
emit([description.hotelId], description); // array as key
}
var contact = getStep('DC', 3, function(result) {
result.email = doc.emailAddress;
result.contact = doc.mainContactName;
});
if (contact != null) {
emit([contact.hotelId], contact); // array as key
}
var location = getStep('LOC', 2, function(result) {
result.city = doc.cityName;
result.zip = doc.postalCode;
result.country = doc.countryName;
result.street = doc.stateName + ', ' + doc.streetName;
});
if (location != null) {
emit([location.hotelId], location); // array as key
}
var property = getStep('PRP', 1, function(result) {
result.paymentMethodId = doc.paymentMethodId
});
if (property != null) {
emit([property.hotelId], property); // array as key
}
}
然后我需要设置group_level=1
和reduce=true
。您可以在视图编辑器或查询字符串中执行此操作。
最后一位是reduce:
function(key, values, rereduce) {
if (rereduce) {
return values;
} else {
var result = {};
values.forEach(function(item){
for(var name in item){
result[name] = item[name];
}
});
return result;
}
}
结果将按预期由 hotelId 合并 :)
我的应用程序将多种文档类型存储在同一个存储桶中。我知道这不是好的做法,但我对可以在服务器上创建的存储桶数量有限制,目前没有办法解决。这些文档以它们的类型为前缀,所以当我得到一个文档时,我只需要连接前缀和 id 来获取密钥,然后我就可以进行密钥查找。
我需要创建一个报告,从多种文档类型中提取信息。
我的地图是这样的:
function(doc, meta) {
var getStep = function(stepName, exit, mapper) {
if (meta.id.indexOf(stepName) !== -1) {
var hotelId = parseInt(meta.id.replace(stepName + '_', ''));
if (hotelId > 0) {
var result = {
hotelId: hotelId,
exit: exit
};
if (mapper !== undefined) {
mapper(result);
}
return result;
}
}
return null;
};
var photos = getStep('PHOTOS', 7);
if (photos != null) {
emit(photos.hotelId, photos);
}
var pricing = getStep('PICR', 5);
if (pricing != null) {
emit(pricing.hotelId, pricing);
}
var owner = getStep('OWNER', 1);
if (owner != null) {
emit(owner.hotelId, owner);
}
var amenity = getStep('AM', 4);
if (amenity != null) {
emit(amenity.hotelId, amenity);
}
var description = getStep('HDESC', 3, function(result) {
result.description = doc.description;
result.hotelRoomTypeId = doc.hotelRoomTypeId;
result.starRating = doc.starRating;
});
if (description != null) {
emit(description.hotelId, description);
}
var contact = getStep('DC', 3, function(result) {
result.email = doc.emailAddress;
result.contact = doc.mainContactName;
});
if (contact != null) {
emit(contact.hotelId, contact);
}
var location = getStep('LOC', 2, function(result) {
result.city = doc.cityName;
result.zip = doc.postalCode;
result.country = doc.countryName;
result.street = doc.stateName + ', ' + doc.streetName;
});
if (location != null) {
emit(location.hotelId, location);
}
var property = getStep('PRP', 1, function(result) {
result.paymentMethodId = doc.paymentMethodId
});
if (property != null) {
emit(property.hotelId, property);
}
}
它生成此输出:
"total_rows":...,"rows":[
{"id":"DC_1","key":1,"value":{"hotelId":1,"exit":3,"email":"test@example.com","contact":"Jeno"}},
{"id":"HDESC_1","key":1,"value":{"hotelId":1,"exit":3,"description":".","hotelRoomTypeId":0,"starRating":5}},
{"id":"LOC_1","key":1,"value":{"hotelId":1,"exit":2,"city":"Barcelona","zip":"1222","country":"Spain","street":"Catalonia, someplacenice"}},
{"id":"PRP_1","key":1,"value":{"hotelId":1,"exit":1}},
{"id":"PRP_2","key":2,"value":{"hotelId":2,"exit":1}},
{"id":"AM_3","key":3,"value":{"hotelId":3,"exit":4}},
{"id":"AM_4","key":4,"value":{"hotelId":4,"exit":4}},
{"id":"PHOTOS_4","key":4,"value":{"hotelId":4,"exit":7}},
{"id":"PRP_4","key":4,"value":{"hotelId":4"exit":1}},
{"id":"AM_4","key":4,"value":{"hotelId":4,"exit":4}},
{"id":"PRP_4","key":4,"value":{"hotelId":4,"exit":1}},
{"id":"PHOTOS_5","key":5,"value":{"hotelId":5,"exit":7}}
...
]
我正在尝试按新键 hotelId 对日期进行分组,并使用自定义缩减器将字段合并到一个文档中。根据错误类型,我收到不同的错误,但所有错误似乎都表明减速器可以 return 的日期有限制。如果我将 return 类型从一个对象更改为一个关联数组,它的工作方式几乎相同,我会得到一个更好的错误。
function(key, values, rereduce) {
if (rereduce) {
return values;
} else {
var results = {}; // Object!
for (var i = 0; i < values.length; i++) {
var row = values[i];
if (!results[row.hotelId]) {
results[row.hotelId] = {
phone: '',
exit: 1
};
}
var result = results[row.hotelId];
for (var name in row) {
result[name] = row[name];
}
if (row.exit > row.exit) {
result.exit = row.exit;
}
};
return results;
}
}
给我 RangeError: Maximum call stack size exceeded
function(key, values, rereduce) {
if (rereduce) {
return values;
} else {
var results = []; // Array!
for (var i = 0; i < values.length; i++) {
var row = values[i];
if (!results[row.hotelId]) {
results[row.hotelId] = {
phone: '',
exit: 1
};
}
var result = results[row.hotelId];
for (var name in row) {
result[name] = row[name];
}
if (row.exit > row.exit) {
result.exit = row.exit;
}
};
return results;
}
}
给我 reduction too large error
function(key, values, rereduce) {
if (rereduce) {
return values;
} else {
return values;
}
}
给我 RangeError: Maximum call stack size exceeded
如果我运行:
function(key, values, rereduce) {
if (rereduce) {
return values;
} else {
return values.length;
}
}
我回来了:
[ 68, 72, 65, 66, 68, 68, 70, 114 ]
JavaScript 引擎应该能够减少最大 114 大小的数组,输出数据应该更小。显然,reduce 可以 return max_kv_size_per_doc
限制多少数据,即 1Mb,也有 10 秒的执行限制,但在我的例子中是另外一回事。有没有办法通过改变算法来绕过这些限制,returning 数组或数组之类的?我可以在地图上做些什么,或者我可以在 rereduce 中使用一些技巧吗?
我明白了。如果我使用复合键和 group_level,它会起作用。
因此,如果我将地图更改为 return 一个数组作为酒店 ID 的键,并且我设置 group_level = 1 那么这些值将按照我最初的预期为我分组:
function(doc, meta) {
var getStep = function(stepName, exit, mapper) {
if (meta.id.indexOf(stepName) !== -1) {
var hotelId = parseInt(meta.id.replace(stepName + '_', ''));
if (hotelId > 0) {
var result = {
hotelId: hotelId,
exit: exit
};
if (mapper !== undefined) {
mapper(result);
}
return result;
}
}
return null;
};
var photos = getStep('PHOTOS', 7);
if (photos != null) {
emit([photos.hotelId], photos); // array as key
}
var pricing = getStep('PICR', 5); // array as key
if (pricing != null) {
emit([pricing.hotelId], pricing);
}
var owner = getStep('OWNER', 1); // array as key
if (owner != null) {
emit([owner.hotelId], owner);
}
var amenity = getStep('AM', 4); // array as key
if (amenity != null) {
emit([amenity.hotelId], amenity);
}
var description = getStep('HDESC', 3, function(result) {
result.description = doc.description;
result.hotelRoomTypeId = doc.hotelRoomTypeId;
result.starRating = doc.starRating;
});
if (description != null) {
emit([description.hotelId], description); // array as key
}
var contact = getStep('DC', 3, function(result) {
result.email = doc.emailAddress;
result.contact = doc.mainContactName;
});
if (contact != null) {
emit([contact.hotelId], contact); // array as key
}
var location = getStep('LOC', 2, function(result) {
result.city = doc.cityName;
result.zip = doc.postalCode;
result.country = doc.countryName;
result.street = doc.stateName + ', ' + doc.streetName;
});
if (location != null) {
emit([location.hotelId], location); // array as key
}
var property = getStep('PRP', 1, function(result) {
result.paymentMethodId = doc.paymentMethodId
});
if (property != null) {
emit([property.hotelId], property); // array as key
}
}
然后我需要设置group_level=1
和reduce=true
。您可以在视图编辑器或查询字符串中执行此操作。
最后一位是reduce:
function(key, values, rereduce) {
if (rereduce) {
return values;
} else {
var result = {};
values.forEach(function(item){
for(var name in item){
result[name] = item[name];
}
});
return result;
}
}
结果将按预期由 hotelId 合并 :)