与邻居一起计算品种（绘制）

Question

我有两个品种：supras 和 subs。

我想画两条线：

拥有超等邻居的订阅者数量（除以总数海龟数量）
邻居数量是潜艇（除以海龟总数）

我该怎么做？我试过这个：

plot count (subs with [one-of neighbors = supras]) / num-turtles
plot count (supras with [one-of neighbors = subs]) / num-turtles

每个人口的数量总是0，不应该是这样的。这是我的代码：

breed [supras supra]
breed [subs sub]

turtles-own [age]
subs-own [status]

to setup
  clear-all

  ;; Color the patches so they're easier to see
  ask patches [ set pcolor random-float 2 ]

  ;; 1/2 of num-turtles patches will sprout subs
  ask n-of (num-turtles / 2) patches [
    if not any? turtles-on patch-set self [
      sprout-subs 1
    ]
  ]

  ;; 1/2 of num-turtles patches will sprout supras
  ask n-of (num-turtles / 2) patches [
    if not any? turtles-on patch-set self [
      sprout-supras 1
    ]
  ]

  ;; Set breed colors and own-variables
  ask subs [
    set color blue
    set shape "dot"
    set age 0
    set status random 10
  ]

  ask supras [
    set color pink
    set shape "dot"
    set age 0
  ]

  reset-ticks
end

to go

  ask turtles [
    let empty-patches neighbors with [not any? turtles-here]
    if any? empty-patches[
      let target one-of empty-patches
      face target
      move-to target
    ]
  ]

  ;; Mating conditions
  ask supras [
    if any? subs-on neighbors [
      ;; Mate with highest status sub
      mate
    ]
  ]

  tick
end

to mate
  move-to max-one-of subs [status]
end

Answer 1

neighbors returns patches 的代理集，所以说 neighbors = supras 不会得到你需要的东西 - 没有补丁是 supras 或subs。相反，您想检查是否有任何邻居有 supras-here 或 subs-here。这对我有用：

plot (count ( subs with [ any? neighbors with [ any? supras-here ] ] ) ) /  ( count turtles )

plot (count ( supras with [ any? neighbors with [ any? subs-here ] ] ) ) /  ( count turtles )

您可能希望将 Y 最大值缩小到 1 以便看到更多内容。

与邻居一起计算品种（绘制）

Counting breeds with neighbors (to plot)

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