我有一个有效的 laravel select 查询。我如何添加过滤器?

I have a working laravel select query. how do i add filters?

大家好吗?提前致谢。
我在 laravel 模型中编写了一个工作函数,该模型执行地理搜索和 returns 按距离搜索的顺序。效果很好。

 public static function searchByDistance($distance, $unit)
{
    //spatial queries
   // $circle_radius = 6371; 
    $circle_radius = 3959; 
    $max_distance = $distance;
    $lat = Auth::user()->getLoc()->latitude;
    $lng = Auth::user()->getLoc()->longitude;
    //get all nearby places
     $nearbyusers = DB::select(
           'SELECT * FROM
                (SELECT users.id, users.country, places.name, places.state_code, places.latitude, places.longitude, (' . $circle_radius . ' * acos(cos(radians(' . $lat . ')) * cos(radians(latitude)) *
                cos(radians(longitude) - radians(' . $lng . ')) +
                sin(radians(' . $lat . ')) * sin(radians(latitude))))
                AS distance
                FROM users
                LEFT JOIN places ON users.suburb=places.name) AS distances
            WHERE distance < ' . $max_distance . '
            ORDER BY distance;
     ');        
   $nearbyusers = (object)$nearbyusers;
    return $nearbyusers;
}

但是我有一个问题。我想调用该函数,return 查询并继续能够对其进行 add ->where() 操作,直到我准备好使用 get() 和 return 结果。

我不能使用 where() or get() 我知道为什么。它的格式不正确。 有没有人可以帮助我 modify/alter 这个功能,这样我就可以在 return $nearbyusers 值后添加更多过滤器?

干杯

看看 official documentation for raw expressions 我想这就是您要找的。无论如何,您必须将原始查询更改为 "builded" 查询,如下所示:

$nearbyusersquery = DB::table('users')
    ->select(DB::RAW('SELECT users.id, users.country, places.name, places.state_code, places.latitude, places.longitude, (' . $circle_radius . ' * acos(cos(radians(' . $lat . ')) * cos(radians(latitude)) *
            cos(radians(longitude) - radians(' . $lng . ')) +
            sin(radians(' . $lat . ')) * sin(radians(latitude))))
            AS distance'))
    ->leftJoin('places', 'users.suburb', '=', 'places.name')
    ->where('distance', '<', $max_distance)
    ->orderBy('distance');      

return $nearbyusersquery

通过这种方式,您的方法将 return 一个可以与其他语句链接的 Builder 对象。

您将要查看底层的 Fluent 查询构建器系统。就目前而言,您的查询是独立的。也有可能这个特定的人可能需要保持独立。

为了以您想要的方式连接到 Fluent,您需要传入查询(这应该会自动解析),添加到其中,然后 return 查询。关于您当前的功能,这可能需要与您所拥有的完全不同的方法(尽管您所拥有的是您希望最终得到的查询的良好模型)。

查看 the docs about query scopes, which may be addressing how you're trying to integrate it. Also, have a look at the code itself, such as this one for the JoinClause function,了解如何构建代码。

基本元素是您需要获取的元素和 return 查询对象。这意味着它不能是静态方法(它需要对象实例),并且根据您采用的方法,您将 returning 传入 $query 对象(范围) 或 $this(它们模型对象的实例本身)。

您需要找到一种方法将您的查询封装到您需要的部分中。它可能是这样的:

public function byDistance($distance, $unit) {
    $lat = Auth::user()->getLoc()->latitude;
    $lng = Auth::user()->getLoc()->longitude;

    return $this->join(DB::select('SELECT users.id, users.country, places.name, places.state_code, places.latitude, places.longitude, (' . $circle_radius . ' * acos(cos(radians(' . $lat . ')) * cos(radians(latitude)) *
            cos(radians(longitude) - radians(' . $lng . ')) +
            sin(radians(' . $lat . ')) * sin(radians(latitude)))
            AS distance'), 
         'users.id', 'distance.user_id = users.id')
    ->leftJoin('places', 'users.suburb = places.name')
    ->where('distance', '<', $distance)
    ->orderBy('distance');
}

请注意查询构建部分中缺少实际的 select(尽管有嵌套的 select),并且缺少任何类型的实际提取。它所做的是添加到当前查询中,然后在最终调用 get 或其他获取函数时构建该查询。这为您提供了一个较大查询的离散片段,您可以在调用它时将其添加到其中。

您也可以使用 sql 来完成。例如:

   $filtr = "";
$filtr2 = "";

If (something)
 $filtr =" and field = var";

If (somethingelse)
   $filtr2 = " and field2 = other_var";

// this can be in the elloquent query
$query = "select .... 
from .... 
Where 1=1 
     $filtr
     $filtr2
";

编辑

//assuming the country Id is passed to your controller
// first initialize the filter as empty string
$countryFilter = "";

// if the country is not null or empty replace the filter
if ($country != null && $country != "")  
    $countryFilter = "and country = $countryFilter";

$nearbyusers = DB::select(
           'SELECT * FROM
                (SELECT users.id, users.country, places.name, places.state_code, places.latitude, places.longitude, (' . $circle_radius . ' * acos(cos(radians(' . $lat . ')) * cos(radians(latitude)) *
                cos(radians(longitude) - radians(' . $lng . ')) +
                sin(radians(' . $lat . ')) * sin(radians(latitude))))
                AS distance
                FROM users
                LEFT JOIN places ON users.suburb=places.name) AS distances
            WHERE distance < ' . $max_distance . '
            -- if no country was selected then it will just be an empty line
            $countryFilter
            ORDER BY distance;
     ');  

嗯,还是老样子,自己解决了。问题很简单。您所要做的就是查找与结果匹配的用户对象并将它们推入数组。然后return那个数组,你就可以使用函数了!所以如果你想从原始查询中获取可传递的对象,这就是你要做的。再次感谢你们提供有用的答案。这个问题真的很简单。最后我摆弄它来工作,而不是从互联网上得到任何答案。

//spatial queries        

                    $circle_radius = 6371;       

                   // $circle_radius = 3959; 


                $max_distance = request('distance');
                $lat = Auth::user()->getLoc()->latitude;
                $lng = Auth::user()->getLoc()->longitude;

                //get all nearby places
                 $nearbyusers = DB::select(
                       'SELECT * FROM
                            (SELECT users.id, users.country, places.name, places.state_code, places.latitude, places.longitude, (' . $circle_radius . ' * acos(cos(radians(' . $lat . ')) * cos(radians(latitude)) *
                            cos(radians(longitude) - radians(' . $lng . ')) +
                            sin(radians(' . $lat . ')) * sin(radians(latitude))))
                            AS distance
                            FROM users
                            LEFT JOIN places ON users.suburb=places.name) AS distances
                        WHERE distance < ' . $max_distance . '
                        ORDER BY distance;
                 ');      

                 $users = [];

                 foreach($nearbyusers as $user)
                 {
                    array_push($users, User::where('id', $user->id)->first());
                 }



               //$nearbyusers = (object)$nearbyusers;


                return Response::json( array( 
                'searchsuccess' => (String) view('members.yessearch', compact('users')) 
                ) );